Answer:
Step-by-step explanation:
This question is a bit sloppy. In higher math courses it would not be permitted. I'll give you the general rule that applies to this question -- sort of.
If you have a triangle that hast angles of 100 50 and 30
The largest side will be opposite the 100 degree angle.
The smallest side will be opposite the 30 degree angle.
So for the question, you are intended to say that CD > AB because CD is opposite a 43 degree angle and AB is opposite a 40 degree angle.
So the answer is Since 43 > 40 then CD>AB
Step-by-step explanation:
by adding :
e=_4
d=24.....
Answer:
Step-by-step explanation:
A) If AB is a diameter, Then ACB is a 90 degrees angle because In a semi-circle (AB is a diameter which divides the circle into 2 equal parts), the angle opposite to the diameter is of 90 degrees.
So, <ACB = 90 degrees
Then <a = 180-90-28
=> <a = 62 degrees
B) The opposite interior angles of a quadrilateral inscribed in a circle add up to 180 degrees.
So,
=> <a + <b = 180
=> <b = 180-62
=> <b = 118 degrees
Answer:
3x-4y=15
7x+y=4
Solve7x+y=4 for y:
7x+y=4
7x+y+−7x=4+−7x (Add -7x to both sides)
y=−7x+4
Step: Substitute −7x+4 for y in 3x−4y=15:
3x−4y=15
3x−4(−7x+4)=15
31x−16=15 (Simplify both sides of the equation)
31x−16+16=15+16 (Add 16 to both sides)
31x=31
(Divide both sides by 31)
x=1
Step: Substitute 1 for x in y=−7x+4:
y=−7x+4
y=(−7)(1)+4
y=−3(Simplify both sides of the equation)
Answer: x=1 and y=−3