Initially there were 12 dogs
dogs left at the end of day =4
number of dogs sold=12-4=8
price of one dog=$104
price of 8 dogs = 104*8= $832
initially there were 8 cats
cats left at the end of day =5
number of cats sold =8-5=3
price of one cat= $25
price of 3 cats =25*3= $75
ratio of sales for dogs to cats = 832/75
Answer:
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.
I think the answer is either 3/49 or about 0.061
hope this helps.
Answer:
chupas trozon
Step-by-step explanation:
pastilla te entra mi trozon