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amid [387]
3 years ago
14

9/17 15/34 6/17 9/34 geometric sequence?

Mathematics
1 answer:
zysi [14]3 years ago
6 0
In a geometric sequence each number after the first is found by multiplying the previous number by a fixed number called the common ratio.

In an arithmetic sequence, each term is equal to the previous term plus or minus a constant called the common difference.

In your problem we have a sequence of numbers that appears to be decreasing in value, but on the surface it doesn't appear to be by any constant number... but if you look closely, the denominator 34 is exactly twice the other denominator 17. This would lead me to look at a common denominator to see if anything takes shape...

9/17 = 18/34
15/34
6/17 = 12/34
9/34

Now we see that each number is the previous number minus 3/34, so we have a common difference of 3/34.

This would match the definition of an arithmetic sequence and NOT a geometric sequence.
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Hey i need to know the answer...
nikitadnepr [17]

Answer: question 6

4/7*8/10 =

first multiply the numeratores the the denominatos.

4*8=32 so this will be numerator.

7*10=70 this is denominator.

so answer is 32/70

same way question 7 is 28/40

question 8

11/2 *9/4 = 99/8= 12 3/8

question 9

convert to improper

9/5*7/3= 63/15 4 3/15

question 10

21/8*16/7= 336/56= 6/6

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please answer question three and four if you can :)<br> Show full working out ty;)
nikklg [1K]

Step-by-step explanation:

3

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

D = ( \frac{2 + 5}{2},  \:  \:  \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \:  \:  \frac{ 1}{2} ) \\ \therefore D= (3.5, \:  \: 0.5) \\  \& \: A=(-1,\:\:4)...(given) \\\\  now \: by \: distance \: formula \\  \\ Length  \: of \:  segment  \: AD \\  =  \sqrt{( - 1 - 3.5)^{2}  +  {(4 - 0.5)}^{2} }  \\ =  \sqrt{(4.5)^{2}  +  {(3.5)}^{2} }  \\ =  \sqrt{20.25 + 12.25 }  \\  =  \sqrt{32.5}  \\    \red{ \boxed{\therefore Length  \: of \:  segment  \: AD  = 5.7 \: units}}

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0
4 years ago
If x=5 then work out 2x^2
lord [1]

Answer 50

given x=5

2x²= 2×5²= 50

5 0
3 years ago
Read 2 more answers
What is the x intercept of the graph of the equation <br> y=x•x-11x+24
yawa3891 [41]
Y = x² - 11x + 24
0 = x² - 11x + 24
x = <u>-(-11) +/- √((-11) - 4(1)(24))</u>
                       2(1)
x = <u>11 +/- √(121 - 96)</u>
                    2
x = <u>11 +/- √(25)
</u>              2
x = <u>11 +/- 5</u>
            2
x = <u>11 + 5</u>      x = <u>11 - 5</u>
           2                   2
x = <u>16</u>            x = <u>6</u>
       2                   2
x = 8              x = 3

The x - intercept of the equation is equal to {8, 3}.
<u />
3 0
3 years ago
PLEASE ANSWER + BRAINLIEST!!!
konstantin123 [22]
Here is the correct answer of the given polynomial above. The answer is [(-3x^2)+(-8x^2)]+4x+[9+5]. The expression that can be used to find the sum of the polynomials given above is [(-3x^2)+(-8x^2)]+4x+[9+5]. 

7 0
3 years ago
Read 2 more answers
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