ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
Answer:
The answer is 4:15
Step-by-step explanation:
17-2V=41
subtract 17 from both sides
-2v =24
v = 24 / -2 = -12
v=-12
128 square inches.
The area of a triangle is 1/2bh, where b is the base and h is the height. Substitute the values in.
1/2 * 8 * 32
Now, just solve.
4 * 32
128 square inches
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Answer:
Which is the output of the formula =AND(12>6;6>3;3>9)?
A.
TRUE
B.
FALSE
C.
12
D.
9