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2 years ago

Two angles are supplementary if their sum is 180 degrees

Mathematics

1 answer:

maksim [4K]2 years ago

8 0

Answer:

maybe 80 degrees and 100? might be wrong dont count on me fully

Step-by-step explanation:

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Divide -2x^3-5x^2+4x+2 by x+2

erik [133]

Answer:

The correct option is C. $-2x^2-x+6, R(-10)$

Explanation:

Given:

Dividend = -2x^3-5x^2+4x+2

Divider =(x+2)

Solution:

Now by using the division method , we will find out the quotient and remainder of the given equation

And the equation will become

$-2x^3-5x^2+4x+2=(x+2)(-2x^2-x+6)-10$

So , We will get the quotient = $-2x^2-x+6$

And Remainder = -10

Hence the Correct option which perfectly satisfy the given equation is C.

4 0

2 years ago

Which expression has a value of 20?

Marysya12 [62]

I couldn't find anyone that led to the answer 20 but the one that ended closest to 20 is the last one.

4 0

2 years ago

Read 2 more answers

Find [5(cos 330 degrees + I sin 330 degrees)]^3

earnstyle [38]

Given a complex number in the form:
$z= \rho [\cos \theta + i \sin \theta]$
The nth-power of this number, $z^n$ , can be calculated as follows:

- the modulus of $z^n$ is equal to the nth-power of the modulus of z, while the angle of $z^n$ is equal to n multiplied the angle of z, so:
$z^n = \rho^n [\cos n\theta + i \sin n\theta ]$
In our case, n=3, so $z^3$ is equal to
$z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]$ (1)
And since
$3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}$
and both sine and cosine are periodic in $2 \pi$ , (1) becomes
$z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]$

6 0

3 years ago

PLEASEEE HELP BEEN STUCK WITH THIS ILL MARK U BRAINLESS PLEASEEEE

andre [41]

there are 18 marbles all together

4 are red

18÷4= 4.5

percent 4.5%

fraction 4 1/2

decimal 4.5

I'm not sure about the second hald but I hope this helped ^^

6 0