E(X) = 0(0.7) + 1(0.2) + 2(0.1) = 0.2 + 0.2 = 0.4
The expected daily loss due to blackouts = 0.4 * $500 = $200
Var(X) = 0(0.7 - 0.4)^2 + 1(0.2 - 0.4)^2 + 2(0.1 - 0.4)^2 = 0.04 + 0.18 = 0.22
The expected daily variance due to blackouts = 0.22 * $500 = $110
Step-by-step explanation:
fifth row=19+4=23
sixth row= 23+4=27
Answer:
x^7 + x^6 - 3x^4 + 4x^3 + 6x - 3.
Step-by-step explanation:
(x3 + 2x - 1) (x4 - x3 + 3)
= x^7 - x^6 + 3x^3 + 2x^6 - 2x^4 + 6x - x^4 + x^3 - 3
= x^7 + x^6 - 3x^4 + 4x^3 + 6x - 3.
