Answer: 2.5 in
Step-by-step explanation:
A paint can is assumed to be a cylindrical shape. The formula for volume of a cylinder is V = Pi * r^2 * h
The volume is 500 mL, which we are told is 30.512 cubic inches
The problem says we can approximate Pi to be 3.14
The height is 6 in
So we need to solve for diameter of the base. In order to do that, solve for the radius first, and since d = 2r, just double the value of the radius
After plugging in what we know to the formula, we get
30.512 in^3 = 3.14 * r^2 * 6 in
30.512 in^3 / (3.14 * 6 in) = r^2
1.619533 in^2(rounded) = r^2
(1.619533 in^2)^(1/2) = l r l
1.272609 in (rounded) = r
Note: on the above step, we can immediately reject the negative solution, because a radius cannot be negative
Now that we have the radius, we simply double it to find the diameter
d = 2r
d = 2 * 1.272609
d = 2.545218
Since the question asked for the diameter rounded to the nearest tenth, the final answer is diameter = 2.5 in
