Question

NEED HELP NOW! A can of paint holds 500 mL of paint and is 6 in. tall. What is the diameter of the can? (Hint: 500

Answer 1

Answer: 2.5 in

Step-by-step explanation:

A paint can is assumed to be a cylindrical shape. The formula for volume of a cylinder is V = Pi * r^2 * h

The volume is 500 mL, which we are told is 30.512 cubic inches

The problem says we can approximate Pi to be 3.14

The height is 6 in

So we need to solve for diameter of the base. In order to do that, solve for the radius first, and since d = 2r, just double the value of the radius

After plugging in what we know to the formula, we get
30.512 in^3 = 3.14 * r^2 * 6 in

30.512 in^3 / (3.14 * 6 in) = r^2

1.619533 in^2(rounded) = r^2

(1.619533 in^2)^(1/2) = l r l

1.272609 in (rounded) = r

Note: on the above step, we can immediately reject the negative solution, because a radius cannot be negative

Now that we have the radius, we simply double it to find the diameter

d = 2r

d = 2 * 1.272609

d = 2.545218

Since the question asked for the diameter rounded to the nearest tenth, the final answer is diameter = 2.5 in