5/(x^2-4)+2/x=2/(x-2) if we factor the leading denominator, it is a "difference of squares" of the form (a^2-b^2) which always factors to (a-b)(a+b) so we have:
5/((x-2)(x+2))+2/x=2/(x-2), to add/subtract fractions we need a common denominator, so in this case we need a common denominator of x(x-2)(x+2) so
5(x)+2(x+2)(x-2)=2(x)(x+2), perform indicated operations...
5x+2(x^2-4)=2x(x+2)
5x+2x^2-8=2x^2+4x subtract 2x from both sides
5x-8=4x subtract 4x from both sides
x-8=0 add 8 to both sides
x=8
check...
5/(x^2-4)+2/x=2/(x-2) when x=8 so
5/(64-4)+2/8=2/(8-2)
5/60+1/4=2/6
5/60+15/60=20/60
20/60=20/60
Answer:
A (NO) B(YES) C(YES)
Step-by-step explanation:
Law of sines is used to find the measurements of angles not sides. Law of cosines is used for the sides. And pythagorean theorum should be obvious as it is based on the sides of a right triangle.
Answer:
B
Step-by-step explanation:
Add whole numbers first 3+3+3= 9
Convert fractions to have same denominators 4/12+3/12+5/12= 1
Add both numbers together 9+1= 10
Answer:
The slop is - 1/2
Step-by-step explanation:
The slop is what x is multiplied by,
Bonus: What you add is the y interspet , in this case 1/4
