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Radda [10]
3 years ago
11

Mexico City, Mexico, is the world's second largest metropolis and is also one of its fastest-growing cities with a projected gro

wth rate of 3.2% per year. Its population in 1991 was 20,899,000 people. Use the formula P = 20.899e^0.032t to predict its population P in millions with t equal to the number of years after 1991. What is the predicted population to the nearest thousand of Mexico City for the year 2010?
Mathematics
1 answer:
Cloud [144]3 years ago
5 0

Answer:

Predicted population of Mexico City in year 2010 = 38386000

Step-by-step explanation:

Formula to be used for the population of Mexico,

P = 20.899e^{0.032t}

Where t = Duration after year 1991

P = Final population

Number of years between 2010 and 1991 = 19 years

Predicted population of Mexico city after 2010 = 20.899e^{0.032\times 19}

                                                                              = 20.899 × (1.8368)

                                                                              = 38.38633 million

                                                                              = 38.386 million

Therefore, predicted population of Mexico City in year 2010 = 38386000

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How many times will the digit "3" appear if we write all whole numbers from 1-9999?
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7 0
3 years ago
Need an answer, please need an answer, please​
trasher [3.6K]

Answer:

Step-by-step explanation:

Area = 192 m²

Perimeter= 56 m

Width = x m

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2*(length + width) = 56

Divide the equation by 2

l + x = 56/2

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2) Equation is a quadratic equation. The roots of this equation will the dimensions of the rectangular plot.

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Product =192

Factors =  -16 , -12   {-16 +(-12) = -28  & (-12)*(-16) = 192}

x² - 28x + 192 = 0

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x(x  -12) - 16(x - 12) = 0

(x - 12)(x -16) =0

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Sum of the roots = half of the perimeter

5) Product of the roots = 12*16 = 192 =  area of the rectangle.

6 0
3 years ago
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