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egoroff_w [7]
2 years ago
15

Factor 16a + 72 to find the equivalent expression

Mathematics
2 answers:
igomit [66]2 years ago
8 0

Answer:

8(2a+9)

Step-by-step explanation:

Hope this helps

Naddik [55]2 years ago
6 0

Answer:

=8\left(2a+9\right)

Step-by-step explanation:

16a+72

\mathrm{Rewrite\:}16\mathrm{\:as\:}8\cdot \:2

\mathrm{Rewrite\:}72\mathrm{\:as\:}8\cdot \:9

=8\cdot \:2a+8\cdot \:9

\mathrm{Factor\:out\:common\:term\:}8

=8\left(2a+9\right)

Hence, the correct answer is  =8\left(2a+9\right)

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Someone please help and thank you
WINSTONCH [101]

Answer:

answer is 51

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Determine the values of X, Y and Z on the following number line:<br> HH<br> X -11 Y 9 Z
Dmitrij [34]
-11 y 17 with z and x on the line
3 0
3 years ago
If each data is increased by a constant K then find it's mean ?? answer fast pleaseeeeeeeeeee​
MArishka [77]

Answer:

The mean is also increased by the constant k.

Step-by-step explanation:

Suppose that we have the set of N elements

{x₁, x₂, x₃, ..., xₙ}

The mean of this set is:

M = (x₁ + x₂ + x₃ + ... + xₙ)/N

Now if we increase each element of our set by a constant K, then our new set is:

{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}

The mean of this set is:

M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N

M' = (x₁ + x₂ + ... + xₙ + N*k)/N

We can rewrite this as:

M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N

and  (x₁ + x₂ + ... + xₙ)/N was the original mean, then:

M' = M + (k*N)/N

M' = M + k

Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.

6 0
3 years ago
You need 3 sticks of butter for every 24 cookies you bake<br>​
andriy [413]

Umm...not sure what your question is, but to make 10 cookies you would need 1.25 sticks of butter, and to make 48 cookies you would need 6 sticks of butter. Hope this helps!

3 0
3 years ago
What is 6+14r-12r+3?
Ugo [173]
<span><span><span>6+<span>14r</span></span>−<span>12r</span></span>+3

</span><span>=<span><span><span><span>6+<span>14r</span></span>+</span>−<span>12r</span></span>+3

</span></span>Combine Like Terms:

<span>=<span><span><span>6+<span>14r</span></span>+<span>−<span>12r</span></span></span>+3

</span></span><span>=<span><span>(<span><span>14r</span>+<span>−<span>12r</span></span></span>)</span>+<span>(<span>6+3</span>)

Your answer would be:
</span></span></span><span><span><span>
2r</span>+<span>9

~Good Luck~</span></span></span>
5 0
3 years ago
Read 2 more answers
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