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Harrizon [31]
3 years ago
8

For what values of y:

Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0

Answer:

y > \frac{3}{17}

Step-by-step explanation:

To solve this problem, simply set the binomial, 5y - 1 as greater than \frac{3y - 1}{4}, and solve for the value of y as you would solve an equation.

Thus:

5y - 1 > \frac{3y - 1}{4}

Multiply both sides by 4

4(5y - 1) > \frac{3y - 1}{4}*4

4*5y - 4*1 > 3y - 1

20y - 4 > 3y - 1

Subtract 3y from both sides

20y - 4 - 3y > 3y - 1 - 3y

17y - 4 > -1

Add 4 to both sides

17y - 4 + 4 > -1 + 4

17y > 3

Divide both sides by 17

\frac{17y}{17} > \frac{3}{17}

y > \frac{3}{17}

Therefore, the value of y that will make the binomial 5y - 1 greater than \frac{3y - 1}{4} is y > \frac{3}{17}.

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For this case we have the following apple picking options, in dozens:

<em>Tyler:</em>

\frac {3} {3} = 1

Tyler picked up a dozen.

<em>Olivia:</em>

\frac {5} {6} = 0.833

Olivia collected 0.833 dozen apples.

<em>Samantha:</em>

\frac {2} {3} = 0.667

Samantha collected 0.667 dozens of apples.

Thus, it is observed that Samantha collected the least amount of apples.

ANswer:

Samantha

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GIVING BRAINLIESTTTTT
andreev551 [17]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

* Lets find the same steps in the constructions

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  "Place the compass on a point on the original line"

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3 years ago
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Answer:

C.(5,5,10)

1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 14, 16, 18, ... 5, 10, 13, 15, 17, 20, 26, 29, 30, 34, 35, ... 25, 50, 75, 100, 150, 169, 175, 200, 225, ...

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2 years ago
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