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Hi there!
The question gives us the quadratic equation , and it tells us to solve it using the quadratic formula, which goes as . However, we must first find the values of a, b, and c. The official quadratic equation goes as , which matches the format of the given quadratic equation. Hence, the value of a would be 1, the value of b would be 5, and the value of c would be 3. Now, just plug it back into the quadratic equation and simplify to get the zeros of the equation.
x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}
x = \frac{-(5) \pm \sqrt{(5)^2 - 4(1)(3)} }{2(1)}
x = \frac{-5 \pm \sqrt{25 - 12} }{2}
x = \frac{-5 \pm \sqrt{13} }{2}
x = \frac{-5 \pm 3.61 }{2}
x = \frac{-5 + 3.61 }{2}, x = \frac{-5 - 3.61 }{2}
x=-0.695 \ \textgreater \ \ \textgreater \ -0.7, x= -4.305 \ \textgreater \ \ \textgreater \ x=-4.31
Therefore, the solutions to the quadratic equation are x = -0.7 and x = -4.31. Hope this helped and have a phenomenal day!
Your answer is 4.31
Answer:
y=x+1
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(3-2)/(2-1)
m=1/1
m=1
y-y1=m(x-x1)
y-2=1(x-1)
y-2=x-1
y=x-1+2
y=x+1
First, we have to get the fractions to common denominators.
4/5 = 16/20
1/4 = 5/20
5 5/20 - 3 16/20 = 1 9/20
She put 1 9/20 extra cups in.
