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2 years ago

Use synthetic division to divide (3y3 – 9y2 – 56y + 8) ÷ (y – 6).

Mathematics

2 answers:

Kaylis [27]2 years ago

7 0

Answer: 3y2 + 9y – 2 R -4

Step-by-step explanation:

That is what LammettHash said the answer is

Tju [1.3M]2 years ago

3 0

Synthetic division yields

$\dfrac{3y^3-9y^2-56y+8}{y-6}=3y^2+9y-2-\dfrac4{y-6}$

See attachment for work

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Geometry math question no Guessing and Please show work thank you

Virty [35]

A, B and C are collinear and B is in the middle.

so we have AB + BC =AC

6x +x-5= 23

7x -5=23

adding 5 to both sides

7x=23+5

7x =28

dividing both sides by 7

we get x=28/7 =4

So answer is x=4

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3 years ago

You draw 2 cards from a deck. What’s the probability that one is red and the other is black

Andreyy89

Answer:

26/52 50%

Step-by-step explanation:

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2 years ago

The cost of a new smart watch at Walmart is

ludmilkaskok [199]

Answer: $50.50

Step-by-step explanation:

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3 years ago

Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0

Arada [10]

Answer:

$b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$

Step-by-step explanation:

The given matrix addition is

$B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

We need to find the elements of matrix B.

Let $B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}$

Substitute the value of matrix.

$\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

After addition of two matrix we get

$\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

On equating both sides.

$b_{11}+15=1\Rightarrow b_{11}=-14$

$b_{12}-7=2\Rightarrow b_{12}=9$

$b_{13}+4=12\Rightarrow b_{13}=8$

$b_{21}+0=4\Rightarrow b_{21}=4$

$b_{22}+1=0\Rightarrow b_{22}=-1$

$b_{23}+2=2\Rightarrow b_{23}=0$

Therefore, the elements of matrix B are $b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$ .

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3 years ago

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3 years ago