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2 years ago

་་བ་ཆེ། འོན་ཏེ་ ས་གནས་ཀྱི འནརས་ན། ན་ནས། ན་བ་ བས་ ཆུ་

Mathematics

1 answer:

spayn [35]2 years ago

5 0

Answer:

???

Step-by-step explanation:

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What is the equation of the line that is perpendicular to y= -3x + 1 and passes through (2,3)?

Aleonysh [2.5K]

Answer:

$\large\boxed{y=\dfrac{1}{3}x+2\dfrac{1}{3}}$

Step-by-step explanation:

$\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=-3x+1\to m_1=-3.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-3}=\dfrac{1}{3}.\\\\\text{The equation of the searched line:}\ y=\dfrac{1}{3}x+b.\\\\\text{The line passes through }(2,\ 3).$

$\text{Put the coordinates of the point to the equation.}\ x=2,\ y=3:\\\\3=\dfrac{1}{3}(2)+b\\\\3=\dfrac{2}{3}+b\qquad\text{subtract}\ \dfrac{2}{3}\ \text{from both sides}\\\\b=2\dfrac{1}{3}$

3 0

3 years ago

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Subtract. Your answer should be a polynomial in standard form. a (4r ^ 2 - 3r + 2) - (- r ^ 2 - 3r) =

blsea [12.9K]

Answer:5r2+2

Step-by-step explanation:

Distribute the Negative Sign:

=4r2−3r+2+−1(−r2−3r)

=4r2+−3r+2+−1(−r2)+−1(−3r)

=4r2+−3r+2+r2+3r

Combine Like Terms:

=4r2+−3r+2+r2+3r

=(4r2+r2)+(−3r+3r)+(2)

=5r2+2

6 0

3 years ago

Vanessa draws one side of equilateral AABC on the coordinate plane at points A(-2, 1) and B(4,1). What are the possible coordina

natulia [17]

Answer:

Step-by-step explanation:

Answer E is the only one that is close

7 0

3 years ago

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The figure below shows circle with center O and two perpendicular diameters

dlinn [17]

Answer:

Triangles OAB,BOC,COD,DOA are isocele and right , are thus equals and have the same hypothenus . The quadrilater ABCD is a diamond (having 4 sides equals) and its diagonals perpendicular is thus a square.

Step-by-step explanation:

3 0

3 years ago

Simplify the expression (m^3)^-1 (x^2)^5

Katyanochek1 [597]

(m^3)^-1 (x^2)^5 = (m^-3) (x^10) = x^10 / m^3

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3 years ago

་་བ་ཆེ། འོན་ཏེ་ ས་གནས་ཀྱི འནརས་ན། ན་ནས། ན་བ་ བས་ ཆུ་​

་་བ་ཆེ། འོན་ཏེ་ ས་གནས་ཀྱི འནརས་ན། ན་ནས། ན་བ་ བས་ ཆུ་