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gladu [14]
2 years ago
7

Find the values of the missing arc or find x

Mathematics
1 answer:
Wittaler [7]2 years ago
4 0

Answer: x=3

Step-by-step explanation:

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The graph shows the function f(x) = 2*<br> What is the value of xwhen f(x) = 8?
soldi70 [24.7K]

Answer:

x=3

Step-by-step explanation:

f(x) = 2^x

Let f(x) =8

8 = 2^x

Rewriting 8 as 2^3

2^3 = 2^x

The bases are the same so the exponents are the same

3=x

3 0
3 years ago
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What is one half divided by three fifths
Harman [31]

Answer:

Fraction: 5/6

Step-by-step explanation:

(1/2) / (3/5) = 1/2 X 5/3 = 0.83333333333

3 0
2 years ago
A ball is thrown with an initial velocity of 32 ft/s from a height of 4.5 feet. It’s height as a function of time is given by th
Lana71 [14]

Answer:

the ball will be in the air for possibly 2.5 seconds and it max hieght was 10 ft

Step-by-step explanation:

no clue

6 0
3 years ago
I GIVEEE BRAINLILSTT
alekssr [168]

Answer:

(x, y)  -->   (x + 14, y + 8)

Step-by-step explanation:

Look at 1 original point and its corresponding translated point.

Let's look at F and F'.

To go from F to F', you need to go right in x 14 units.

Then you need to go up in y 8 units.

The translation rule is to add 14 to x and 8 to y.

(x, y)  -->   (x + 14, y + 8)

4 0
2 years ago
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A sample of 15 data is as follows: 17, 18, 17, 17, 13, 18, 5, 5, 6, 7, 8, 9, 20, 17, 3. The mode of the data isa)4b)13c)17d)20Co
Degger [83]

The mode of the data of sample with 15 values is c) 17.

The mode of any sample of data can be calculated by finding the number that is present highest number of times. Based on this, we will look for the numbers that are present multiple times in the mentioned sample.

17, 18 and 5 are the three numbers that are present more than once. Now, let's see what is the frequency of each of these numbers.

Frequency of 17 - 4

Frequency of 18 - 2

Frequency of 5 - 2

Thus, the number 17 is present maximum number of times and hence is the mode of the data.

Learn more about mode -

brainly.com/question/14532771

#SPJ4

5 0
1 year ago
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