Answer:
5120oz/12=426.667 ounces.
Step-by-step explanation:
We know 1 pound = 16 oz. If we want to find out how many ounces are in 320 lbs, we must multiply 16 by 320 = 5120 ounces. Now we must divide by 12 to see how much she ate per month. 5120 divided by 12 is 426.667 or 426 and 2/3 ounces per month.
Alternatively, we can set up a proportion 1 lb / 16 ounces = 320 lb / x ounces. We cross multiply 1 times x = 320 times 15. On the left hand side we just have x and on the right hand side we get 5120. Hence, x=5120 ounces per year. To find how many she ate per month we must divide by 12 since there are 12 months in a year. So it comes out to 426 and 2/3 ounces per month.
Here are the equations: (1lb)(320lb)=(16oz)(320oz) implies 320lb=5120oz. Then divide 5120oz 12 to get how much she ate per month: 5120oz/12=426.667 ounces.
Answer:
(y¹-y¹/x¹-x¹)
8-11/10-19
-3/-9
1/3
Step-by-step explanation:
1/3 or one-third is your answer!
Answer:
Step-by-step explanation:
It would be c cause it is possible to land on yellow
Answer: Josh borrowed $ 876 to buy the computer.
Step-by-step explanation:
Formula for simple interest : I = Prt
, where P = principal amount
r= rate of interest ( in decimal)
t=time (in years)
Total amount with simple interest to pay : A = P+I
⇒ A = P +Prt
⇒ A = P(1 +rt) (i)
As per given , A = $1,244.34
r= 12.4% = 0.124
t= 3 years
Now, put these values in (i) , we get
Hence, Josh borrowed $ 876 to buy the computer.
Answer:
Real numbers for both
Step-by-step explanation:
The domain of a function is the set of values that the unknown t can adopt. For this function, t can be any real number as there are no restrictions for the t. Ir can be any positive number, 0, negative numbers, fractions, irrational numbers, whatever number you like.
The range of a function is the values that p(t) adopt when we replace the t value with any number. Here, again, it range is all real numbers. If you want p(t) to be positive it is possible, negative is possible, 0 is possible, and so on. If you like, you can verify it by replacing the numbers you like.
Something to know is that linear polynomial functions ALWAYS have their domains and ranges in real numbers.
