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FinnZ [79.3K]
3 years ago
7

Is 3x + 12 +x and 4 (3 + x) equivalent .Why and Whynot?

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0

Answer: They are

Step-by-step explanation: the first one you add both terms of x’s and you get 12+4x. The second one you use the distributive property, 4*3+4*x and get 12+4x.

Luden [163]3 years ago
4 0

Answer:

no because yes 4 multiplied by 3 its x but the 4 can still not replace the x

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Mrs. Larsen made 12 pillow from 16 yards of the same fabric. How much fabric was used to make each pillow? Between what two whol
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Answer:

1.3333333333333 in between 1 and 2

Step-by-step explanation:

Do long division

16/12=1 remainder 4

40/12=3 remainder 4

answer is 1. followed by infinite 3's

A number with a decimal is in between the next whole number and the whole number itself.

7 0
3 years ago
use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r
Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt

If we ask that f has continuous (n+1)th derivative we can apply the mean value theorem for integrals. Then, there exists c between a and x such that

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x

Hence,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .

Thus,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}

and the Taylor theorem with Lagrange remainder is

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}.

Step-by-step explanation:

5 0
3 years ago
): How many times longer is the diameter of a grain of sand than the diameter of the average cell in the human body? Show your w
Airida [17]
<span>Approximately 25. Of the 5 grades of sand used in the United states, medium sand has particles ranging from 0.25 mm to 0.5 mm. For convenience, I'll use 0.5mm as the diameter of a grain of sand. Human cells range from a volume of 30 cubic micrometers (human sperm cell) up to 4 million micrometers (human egg cell). For the average human cell, I'll use an osteoblast with a volume of 4000 cubic micrometers or a diameter of 2x10^-5 meters. Now just take the diameter of a grain of sand and divide by the diameter of a human cell. 5 x 10^-4 / 2x10^-5 = 5/2 x 10^(-4 - -5) = 2.5x10^1 = 25 So the diameter of a grain of sand at 0.5 mm is approximately 25 times larger than that of a human cell at 0.02mm</span>
4 0
4 years ago
The triangles are congruent. Write the<br><br>congruence statement (LT#4)
gogolik [260]

Answer:

C

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8 0
3 years ago
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Answer: d

Step-by-step explanation:

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