Answer:
2587mm^3 approx!
Step-by-step explanation:
first you divide the nut into 6 part(in triangle now, by joining centre to each edge)
let's take one part of the triangular shape then area of that part can be found by using 1/2×base×height
i.e, 1/2×13×15=97.5(mm^2)
now when we consider depth of that traingular part,we will get volume of that part as area×depth
i.e, 97.5×6=585(mm^3)
now volume of all the 6 triangular part is 585×6=3510(in mm^3)
now take circular cavity in consideration, it's volume will be π(7^2)6=923(mm^3) approximately
now reqired volume will be volume of that hexagonal part minus that of circular cavity
=3510-923
=2587mm^3
✌️
There’s no pictures/angles to this?
Good evening
Answer:
Step-by-step explanation:
g(x) = -20
⇔
3x-1 = -20
⇔
3x = -20 + 1
⇔
3x = -19
⇔
x = -19/3
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:)
2 and 37/100 so I'm pretty sure yes it can be simplified
