The density of water is 1000 kilograms per cubic meter, and the density of ice is about 916 kilograms per cubic meter. If 575 ki
lograms of water and 275 kilograms of ice is combined in a container, about how much volume would the mixture take up?
1 answer:
Answer:
volume of the mixture is (0.575+0.300)-----> 0.875 m³
Explanation:
we know that
density=mass/volume--------> volume=mass/density
step 1
find the volume of water
mass=575 kg
density of water=1000 kg/m³
volume of water=mass/density-----> 575/1000----> 0.575 m³
step 2
find the volume of ice
mass=275 kg
density of ice=916 kg/m³
volume of ice=mass/density-----> 275/916----> 0.300... m³
the volume of water is 0.575³
the volume of ice is 0.300.. m³
volume of the mixture is (0.575+0.300)-----> 0.875 m³
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