2 years ago

What is the value of \sqrt{21} rounded to the nearest tenth

Mathematics

1 answer:

mixer [17]2 years ago

7 0

Answer:

4.5

explanation:

4.5 x 5(This number is not exactly important, but is used as an example)

Is extremely close to the true square root of 21.

That is 4.58257569495584 <em>unrounded.</em>

You might be interested in

How to solve y in -(y+9)=10

Allisa [31]

Answer:

Step-by-step explanation:

- (y+9) = 10

Multiply through by -1 gives us

y+9 = -10

Subtract 9 from both sides

y = -19

That's your answer.

If you work it through it satisfies the equation.

That is:

- (-19 +9) = 10

-(-10) = 10

10 = 10

Boo ya!

5 0

3 years ago

Mike, Luke, and Alex each own a white hat marked with the first letter of their name. Winter owns a plain red hat, which is not

Karo-lina-s [1.5K]

Answer:switch mikes Luke’s and Alex in between each other and let winter keep her own

Step-by-step explanation:

7 0

2 years ago

A rectangular solid has a base with length 2 centimeters and a width of 8 centimeters. If the volume of the solid is 160 centime

Whitepunk [10]

10 centimeters it is 160/8=20/2=10

8 0

3 years ago

X-8>-3 inequality solution

natka813 [3]

You can add 8 to both sides so you get
x>5

6 0

3 years ago

Will someone help with this ! I was allowed a retry for it and I don’t know how to do it

pashok25 [27]

Answer:

$\frac{dN}{dt}=k(725-N)\\separating the variables and integrating\\\int \frac{dN}{725-N}=\int kdt+c\\-log (725-N)=kt+c\\log (725-N)=-kt-c\\(725-N)=e^{-kt-c} =e^{-kt} *e^{-c} =Ce^{-kt} \\when t=0,N=400\\725-400=Ce^{0} =C\\C=325\\when t=3,N=650\\725-650=325e^{-3k} \\\frac{75}{325}=(e^{-k})^3\\\\e^{-k} =(\frac{3}{13}) ^{\frac{1}{3} } \\when t=5\\725-N=325(\frac{3}{13}) ^{\frac{5}{3} } =325*\frac{3}{13}*(\frac{3}{13} )^{\frac{2}{3}}\\N=725-75*(\frac{3}{13} )^{\frac{2}{3} }=725-28=697$

Step-by-step explanation:

6 0

3 years ago