Question

An airplane flying into a headwind travels the 1890-mile flying distance between two cities in 3 hours. On the return flight, the airplane travels this distance in 2 hours and 30 minutes. Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.

Answer 1

Answer:

Velocity (against wind) = 1,890 / 3 = 630 mph

Velocity (with the wind) = 1,890 / 2.5 = 756 mph

Plane speed (still air) = 630 + wind speed

Plane speed (still air) = 756 - wind speed

Adding both equations equals

2 * Plane speed (still air) = 1,386

Plane Speed = 693 mph

Source: https://www.1728.org/veloccal.htm

Step-by-step explanation: