Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph
To Find : Maximum profit , breakeven point , profit interval
Solution:
The maximum profit the florist will earn from selling celebration bouquets is $ 675
peak of y from Graph
The florist will break-even after Selling 20 one-dollar decreases.
at breakeven
Break even is the point where the profit p(x) becomes 0
The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).
after 20 , P(x) is - ve
Answer:

Step-by-step explanation:
sin =opposite/hypotenuse
sinQ=5/6
(a) If <em>f(x)</em> is to be a proper density function, then its integral over the given support must evaulate to 1:

For the integral, substitute <em>u</em> = <em>x</em> ² and d<em>u</em> = 2<em>x</em> d<em>x</em>. Then as <em>x</em> → 0, <em>u</em> → 0; as <em>x</em> → ∞, <em>u</em> → ∞:

which reduces to
<em>c</em> / 2 (0 + 1) = 1 → <em>c</em> = 2
(b) Find the probability P(1 < <em>X </em>< 3) by integrating the density function over [1, 3] (I'll omit the steps because it's the same process as in (a)):

Answer:
25
Step-by-step explanation:
Given that:
Initial payment done for buying the phone = $50
Charges per month for the phone = $25 per month
To find:
The equation to represent the situation and its slope.
Solution:
First of all, let us assume that
represents the number of months for which monthly is to be made.
Charges paid for one month = $25
Charges paid for
months = $25
Total cost of the phone = Initial payment + Charges paid for
months

It is a linear equation between two variables
and
.
This equation can be compared with slope intercept form of a line.
Slope intercept form of a line is represented by:

is the slope.
On Comparing, we get:

Therefore, the slope is <em>25</em>.