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Rzqust [24]
2 years ago
10

The following table represents the sample space of rolling two number cubes. 1 2 3 4 5 6 1 1-1 1-2 1-3 1-4 1-5 1-6 2 2-1 2-2 2-3

2-4 2-5 2-6 3 3-1 3-2 3-3 3-4 3-5 3-6 4 4-1 4-2 4-3 4-4 4-5 4-6 5 5-1 5-2 5-3 5-4 5-5 5-6 6 6-1 6-2 6-3 6-4 6-5 6-6 How many favorable outcomes are there for the event "rolling exactly one even number"? 27 9 18 16
Mathematics
1 answer:
SOVA2 [1]2 years ago
3 0

Answer:

18

Step-by-step explanation:

Half of the possibilities include 1 even number

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last week the game system was $450. This week the system is on sale for $337.50. By what percent is the price reduced?
zheka24 [161]
25% reduced
you take 337.50 divide by 450 which gives you .75
so you take 100% minus 75% and you get 25%

you can check the work by taking 450 time .25 which gives you 112.5 . and subtract that from 450 you'll end up with 337.50
8 0
3 years ago
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Slav-nsk [51]

Answer:

Graph A fails the vertical line test

Step-by-step explanation:

The vertical line test will fail when a vertical line touches two or more points on the graph

Graph A will fail the vertical line test.  The y axis touches two points on the graph.

6 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
2 years ago
Read 2 more answers
X + 8 = 9. Find the value of x.
algol [13]

Answer:

x = 1

Step-by-step explanation:

x + 8 = 9

=> x = 9 - 8

=> x = 1

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Anna35 [415]

Answer:

1. 30x + 20

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Step-by-step explanation:

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