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Marrrta [24]
2 years ago
5

Samantha has a shelf that is 95 over 4 inches wide. How many books can Samantha arrange on the shelf if each book is 5 over 4 in

ches thick? Work it out.
Mathematics
1 answer:
erastovalidia [21]2 years ago
7 0

Answer:

19 books

Step-by-step explanation:

95/4÷5/4=19bks

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6 children and 2 adults are going to the circus. Children tickets are on sale,half price of adult tickets totaling $54. How much
Anon25 [30]

Answer:

Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.

Step-by-step explanation:

Given:

Number of adults = 2

Number of Children = 6

Total Amount of tickets sold = $54.

We need to find the price of one children's ticket and one adult ticket.

Solution:

Let the Cost of 1 adult ticket be 'x'.

Now Given:

Children tickets are on sale,half price of adult tickets.

Cost of 1 Children ticket = \frac{1}{2}x

Total Amount is equal to Number of adults multiplied by Cost of adult ticket plus Number of Children multiplied by Cost of Children ticket.

Framing in equation for we get;

2x+\frac{1}{2}x\times 6=54\\\\2x+3x=54\\\\5x=54\\\\x=\frac{54}{5} = \$10.8

Cost of 1 adult ticket = $10.8

Cost of 1 children ticket = \frac{x}{2}=\frac{10.8}{2} = \$5.4

Hence Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.

7 0
3 years ago
What is the mslope and y-intercept
attashe74 [19]

Step-by-step explanation:

the y intercept is where 0= x

(0,y)

m is 5

7 0
3 years ago
Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen
SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ =  \frac{4!}{1! (4 - 1 )!} × \frac{6!}{2! (6 - 2 )!}

                                                                            = \frac{4!}{(3)!} × \frac{6!}{2! (4)!}

                                                                            = \frac{4.3!}{(3)!} × \frac{6.5.4!}{2! (4)!}

                                                                            = 4 × \frac{6.5}{2.1! }

                                                                            = 4 × 15 = 60

Total Number of possibility = ¹⁰C₃ = \frac{10!}{3! (10-3)!}

                                                        = \frac{10!}{3! (7)!}

                                                        = \frac{10.9.8.7!}{3! (7)!}

                                                        = \frac{10.9.8}{3.2.1!}

                                                        = 120

So, probability = \frac{60}{120} = \frac{1}{2} = 0.5

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility  = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility   = ⁴C₀ × ⁶C₃

                   =  \frac{4!}{0! (4 - 0)!} × \frac{6!}{3! (6 - 3)!}

                   = \frac{4!}{(4)!} × \frac{6!}{3! (3)!}

                   = 1 × \frac{6.5.4.3!}{3.2.1! (3)!}

                   = 1× \frac{6.5.4}{3.2.1! }

                   = 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = \frac{80}{120} = \frac{8}{12} = 0.66

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility  = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility   = ⁴C₂ × ⁶C₁

                   =  \frac{4!}{2! (4 - 2)!} × \frac{6!}{1! (6 - 1)!}

                   = \frac{4!}{2! (2)!} × \frac{6!}{1! (5)!}

                   = \frac{4.3.2!}{2! (2)!} × \frac{6.5!}{1! (5)!}

                   = \frac{4.3}{2.1!} × \frac{6}{1}

                   = 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility   = ⁴C₃ × ⁶C₀

                   =  \frac{4!}{3! (4 - 3)!} × \frac{6!}{0! (6 - 0)!}

                   = \frac{4!}{3! (1)!} × \frac{6!}{(6)!}

                   = \frac{4.3!}{3!} × 1

                   = 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = \frac{100}{120} = \frac{10}{12} = 0.83

3 0
3 years ago
Fatima earned 6 more than twice as many dollars as Noora. If Fatima earned 40 QR, how much did Noora earn?
-Dominant- [34]
86.
Fatima has 40
Nora has “6 + (40 x 2)”
6+(80) = 86
4 0
3 years ago
(7*10^5)^2 simplified in scientific notation
coldgirl [10]
♥ Lets solve this:
(7*10^5)^2(7*10^5)^2
Starting with 10^5
10*10*10*10*10
We get <span>100000
<span>Now we have 7*100000
Solve for that:
We get </span></span><span>700000
Now we have </span><span>700000^2
Solve for that
We get </span><span>490000000000
and in Scientific notation that is
4.9*10^11</span>
5 0
3 years ago
Read 2 more answers
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