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solniwko [45]
2 years ago
9

Alma was given some money as a gift and deposited it into a savings account. She makes a withdrawal of the same amount at the en

d of each month. At the end of the 5th month, her balance was $442. At the end of the 13th month, her balance was $226.
What is the input?
O- the monthly withdrawal
O- the number of months
O- the balance of the account
O- the starting amount in the account

What is the output?
O- the monthly withdrawal
O- the number of months
O- the balance in the account


What are the two points described in the real-world scenario?
O- (442, 5) and (226,13)
O- (5, 226) and (13, 442)
O- (5, 442) and (13, 226)
O- (442, 13) and (226. 5)
Mathematics
1 answer:
Kryger [21]2 years ago
5 0

Answer:

input= starting amount

output= withdrawals

(5,442) and (13,226)

Step-by-step explanation:

for input its what you put in the account for output its for what you take out.

And for the two points it the months first then you put how much money was left .

Hope this helps!

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If 15 oranges cost Rs. 70,how much do 39 oranges cost ?​
Minchanka [31]

Answer:

  1. firstly divide 70 by 15 and when the product came multiply it with 39

Step-by-step explanation:

70 ÷ 15 = 4.66

4.66 × 39 = 181.974

7 0
3 years ago
Solve the equation for u.<br> Uw + uq=r
soldi70 [24.7K]

Answer:  u= \frac{r}{w+q}

Step-by-step explanation:

uw + uq = r To solve for u  factor  the left side to eliminate the other variables.

u ( w + q) = r   Now divide both sides by w+q

u = \frac{r}{w+q}

4 0
3 years ago
Read 2 more answers
Which fraction is less than the fraction represented by the model?
wolverine [178]

Answer:

The last option.

Step-by-step explanation:

First answer = 6/8

Second answer= 5.5/8

Third answer= 6.5/8

Fourth answer= 4/8

Fourth answer is correct.

3 0
2 years ago
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The product of complete numbers<br> (4, 6) and (5-6) is ?
alexdok [17]

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(38,9)

Step-by-step explanation:

4 0
2 years ago
Determine the asymptotes of the function: y=x^3-5x^2+4x-25/x^2-4x+3
igomit [66]

Answer:

Vertical A @ x=3 and x=1

Horizontal A nowhere since degree on top is higher than degree on bottom

Slant A @ y=x-1  

Step-by-step explanation:

I'm going to look for vertical first:

I'm going to factor the bottom first:  (x-3)(x-1)

So we have possible vertical asymptotes at x=3 and at x=1

To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)

3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3

Let's check x=1

1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also

There is no horizontal asymptote because degree of top is bigger than degree of bottom

There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)

                       x   -1

                --------------------------------------------------

x^2-4x+3 |      x^3-5x^2+4x-25

                  - ( x^3-4x^2+3x)

                   --------------------------------

                            -x^2 +x  -25

                       -   (-x^2+4x-3)

                          ---------------------

                                   -3x-22

So the slant asymptote is to x-1

8 0
3 years ago
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