Please refer to this. Here is the oxidation number of nitrogen in aluminum nitride, aln. <span>Since AlN has 0 charge and Al has +3 charge; charge for N = 0 - (+3) = -3. Hope this is the answer that you are looking for. Have a great day ahead!</span>
Answer:
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We use the formula:
ΔP = (ΔH / ΔV) ln(T2 / T1)
where,
ΔH = change in enthalpy from solid to liquid = 4810 J/mol
ΔV = change in volume from solid to liquid = 0.55 cm^3/mol
T2 = 620 K, T1 = 600 K
So,
ΔP = (4810 / 0.55) ln(620 / 600)
ΔP = 286.76 J/cm^3
or converting to atm:
<span>ΔP
= 2830 atm</span>