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sineoko [7]
3 years ago
15

Major groups of minerals include _____. oxides and carbonates ions and isotopes inorganics and halides silicates and magnetics

Chemistry
2 answers:
erastova [34]3 years ago
5 0

oxides and carbonates, grad point..

mash [69]3 years ago
3 0
The  major    groups  of  minerals  includes: carbonate   ions  and oxides,  .  In  addition  to   this   three  groups   the    following   are   also  the  major   groups   of    minerals
native   elements
sulfate
sulfides
halides
silicate
nitrate       among   others  such   as  phosphate  and vanadate

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Please help i cant find any answers...
Hitman42 [59]

Answer:

98.8

Explanation:

CsF + XeF6 --> CsXeF7

37.8g ................. ?g

37.8g CsF x (1 mol CsF / 151.9g CsF) x (1 mol CsXeF7 / 1 mol CsF) x (397.2g CsXeF7 / 1 mol CsXeF7) = 98.8g CsXeF7 .......... to three significant digits

8 0
2 years ago
Read 2 more answers
Hydrochloric acid reacts with sodium hydroxide to form water and sodium chloride. Hydrochloric acid is an extremely acidic, clea
Brut [27]

The answer is C.

You're welcome!

7 0
2 years ago
The density of silver is 10.5 g/cm3. what would be the mass (in grams) of a piece of silver that occupies a volume of 23.6 cm3?
Keith_Richards [23]
Hey there : !

density = 10.5 g/cm³

volume = 23.6 cm³

therefore:

D = m / V

10.5 = m / 23.6

m = 10.5 * 23.6

m = 247.8 g

hope this helps!
6 0
2 years ago
Read 2 more answers
PLEASE SUSCRIBE MY BROTHER CHANNEL​
Ludmilka [50]

Answer:

Explanation:

ok!

5 0
3 years ago
Read 2 more answers
Two cylinders are made of the same material. Cylinder A is one-fourth (1/4) the length of cylinder B and it has a radius that is
tankabanditka [31]

Answer:

M_{A} : M_{B}  = 4 : 1

Explanation:

Given that:

Volume of a cylinder = \pir^{2}h

For cylinder A, l_{A} = h_{A} = \frac{1}{4} l_{B} and r_{A} = 4r_{B}.

Volume of cylinder A = \pi(4r_{B}) ^{2} × \frac{1}{4} l_{B}

                                   = 4\pir_{B} ^{2} l_{B}

Volume of cylinder B =  \pi(r_{B}) ^{2} l_{B}

                                  =  \pir_{B} ^{2}l_{B}

To determine the ratio of their masses, density (ρ) is defined as the ratio of the mass (M) of a substance to its volume (V).

i.e    ρ = \frac{M}{V}

Thus, since the cylinders are made from the same material, they have the same density  (ρ). So that;

density of A = density of B

density of A = \frac{M_{A} }{4\pi r_{B} ^{2}l_{B}    }

density of B = \frac{M_{B} }{\pi r_{B} ^{2}l_{B}  }

⇒            \frac{M_{A} }{4\pi r_{B} ^{2}l_{B}    }  =  \frac{M_{B} }{\pi r_{B} ^{2}l_{B}  }

The ratio of mass of cylinder A to that of B is given as;

                       \frac{M_{A} }{M_{B} }  =  \frac{4\pi r_{B} ^{2} l_{B}  }{\pi r_{B} ^{2} l_{B}  }

⇒                        \frac{M_{A} }{M_{B} } = \frac{4}{1}

Therefore, M_{A} : M_{B}  = 4 : 1

8 0
3 years ago
Read 2 more answers
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