All categories

3 years ago

I don't get this. I could really use help.

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

6 0

The y intercept is what the y value is when x is 0.

Set X to 0 and solve:

-2/9(0) + 1/3

0 + 1/3 = 1/3

The y-intercept is 1/3

You might be interested in

What is 4x-3=92 when you solve the answer

mixas84 [53]

4x-3=92
4x=92+3
4x=95
$x= \frac{95}{4} \\ x=23\frac{3}{4} \\ x=23,75$

3 0

3 years ago

Read 2 more answers

Need help on this please! (Will mark brainliest)

natima [27]

I’m not 100% sure but it might be 6x6 u should download mayhway .. it’s a good app

6 0

3 years ago

There is a total of 36 books on the bookshelf. The number of hardback books is 15 more than twice the number of paperback books.

uranmaximum [27]

The number of hardback books that are on the bookshelf is 29 books.

Let the total number of books be T.

Let the number of hardback books be H.

Let the number of paperback books be P.

<u>Given the following data:</u>

Total number of books = 36 books

To determine the number of hardback books that are on the bookshelf:

Translating the word problem into an algebraic expression, we have;

The total number of books is:

$T = H+P$

The number of hardback books is 15 more than <u>twice</u> the number of paperback books:

$H =2P+15$

Substituting the given parameters into the formula, we have;

$36 = 2P+15+P\\\\36=3P+15\\\\3P=36-15\\\\3P=21\\\\P=\frac{21}{3}$

P = 7 books

For number of hardback books:

$H =2P+15\\\\H=2(7)+15\\\\H=14+15$

H = 29 books

Read more on word problem here: brainly.com/question/24604067

3 0

2 years ago

Who was the president before obama

BartSMP [9]

The president before Obama was George W. Bush

3 0

3 years ago

The HCF of two numbers is 175. The LCM of these two numbers is 12600. Both numbers are greater than their HCF. Find the two numb

Serjik [45]

Answer:

Hello,

Answer : 1400 and 1575

Step-by-step explanation:

Let's say a and b the ywo numbers

$HCF(a,b)=a\vee b=175=5^2*7\\LCM(a,b)=a\wedge b=12600\\\\a*b=(a\vee b)*(a\wedge b)=(2^3*3^2*5^2*7)*(5^2*7)=2^3*3^2*(5^2*7^2)^2\\\\Both\ numbers\ are\ greater\ than\ their HCF\\a=175*k_1\\b=175*k_2\\\\k_1=2^3\ and\ k_2=3^2\\\\a=175*2^3=1400\\b=175*3^2=1575\\\\$

4 0

3 years ago

I don't get this. I could really use help.​

I don't get this. I could really use help.