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DerKrebs [107]
2 years ago
11

Assume you are saving $1,000 by depositing into a bank CD account with one year until maturity. The interest rate on your deposi

t is 10% and inflation is expected to be 4% over the next year
a. How much money will you have in your bank account at the end of one year?

b. What is the real interest rate you expect to earn on your deposit over the next year?

c. If you are saving for a gaming computer that currently sells for $1,090, will you have enough money from the savings to buy it next year?
Business
1 answer:
mina [271]2 years ago
7 0

The amount of money that I would have in the bank account at the end of one year is $1,100.

The real interest rate I would expect to earn on the deposit is 6%.

If I am saving for a gaming computer, at the end of next year I would have enough money.

<h3>What is the value of the money by next year?</h3>

The formula that can be used to determine the money in my bank account next year is:

FV = P (1 + r)^n

Where:

FV = Future value

P = Present value

R = interest rate

N = number of years

1000 x (1.1)^1 = $1,100

<h3>What is the real interest rate?</h3>

The real interest rate is the nominal interest rate less inflation rate.

The real interest rate = 10% - 4% = 6%

To learn more about future value, please check: brainly.com/question/18760477

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Peter Parker, CEO at Spdey Enterprises, finds his profits at $8,000,000 inadequate for his Web-Slinger business. His production
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Answer:

Spdey Enterprises

The percentage improvement in Sales to achieve the desired profit is:

c. 42.86% increase in sales.

Explanation:

a) Data and Calculations:

Normal profit level = $8 million

Expected profit level = $14 million

                                             Normal            Expected

Sales per year              $40,000,000          $57,142,857

Cost of purchases          16,000,000            22,857,143

Production costs            10,000,000             14,285,714

Variable costs               26,000,000            37,142,857

Total contribution        $14,000,000       $20,000,000

Fixed costs                      6,000,000           6,000,000

Profit level                     $8,000,000        $14,000,000

Expected Contribution = Expected profit level + Fixed Costs

Normal Contribution = 35% of Sales

Normal Variable costs = 65% (100% - 35%)

Expected Contribution = $20,000,000 = 35% of Sales

Therefore, Expected Sales = $57,142,857 ($20,000,000/35%)

Normal Sales = $40,000,000

Expected Sales = $57,142,857

Percentage increase = 42.86% ($57,142,857 - $40,000,000)/$40,000,000

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According to a 2018 article in Esquire magazine, approximately 70% of males over age will develop cancerous cells in their prost
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Answer:

a) Probability of prostrate cancer given a positive test is P(C|+) = 0.0213

b) Probability of cancer given a negative test is P(C|-) = 0.0161

c) Probability of prostrate cancer given a positive test is P(C|+) = 0.3137

d) Probability of cancer given a negative test is P(C|-) = 0.2553

Explanation:

Probability male patient has prostate cancer, P(C) = 0.02

Probability male patient does not have prostrate cancer P(C') = 1 - 0.02 = 0.98

Probability of a positive test given there is no cancer, i.e. P(false positive) = P(+|C') = 0.75

P(negative test given there is cancer) = P(false negative) = P(-|C) = 0.2

P(negative test given there is no cancer) is the complement of P(+|C') = P(-|C') = 1 - 0.75 = 0.25

Probability of positive test given there is prostrate cancer, P(+|C) is the complement of P(-|C), = 1 - 0.2 = 0.8.

a) Probability of prostrate cancer given a positive test is P(C|+)

According to Baye's theorem, P(C|+) = P(+|C)P(C)/P(+)

For P(+), we use the Law Of Total Probability: P(+) = P(+|C)P(C) + P(+|C')P(C')

P(+) = (0.8 * 0.02) + (0.75 * 0.98) = 0.751

Therefore, P(C|+) = P(+|C)P(C)/P(+)

P(C|+) = (0.8 * 0.02)/0.751 = 0.0213

b) Probability of cancer given a negative test is P(C|-)

According to Baye's theorem, P(C|-) = P(-|C)P(C)/P(-)

P(-) = P(-|C)P(C) + P(-|C')P(C')

P(-) = (0.2 * 0.02) + (0.25 * 0.98) = 0.249

Therefore, P(C|-) = (0.2 * 0.02)/0.249

P(C|-) = 0.0161

Part 2: Given the following;

Probability male patient has prostate cancer, P(C) = 0.3

Probability male patient does not have prostrate cancer P(C') = 1 - 0.3 = 0.70

Probability of a positive test given there is no cancer, i.e. P(false positive) = P(+|C') = = 0.75

P(negative test given there is cancer) = P(false negative) = P(-|C) = 0.2

P(negative test given there is no cancer) is the complement of P(+|C') = P(-|C') = 1 - 0.75 = 0.25

Probability of positive test given there is prostrate cancer, P(+|C) is the complement of P(-|C), = 1 - 0.2 = 0.8.

c) Probability of prostrate cancer given a positive test is P(C|+)

According to Baye's theorem, P(C|+) = P(+|C)P(C)/P(+)

For P(+), we use the Law Of Total Probability: P(+) = P(+|C)P(C) + P(+|C')P(C')

P(+) = (0.8 * 0.3) + (0.75 * 0.7) = 0.751

Therefore, P(C|+) = P(+|C)P(C)/P(+)

P(C|+) = (0.8 * 0.3)/0.765 = 0.3137

d) Probability of cancer given a negative test is P(C|-)

According to Baye's theorem, P(C|-) = P(-|C)P(C)/P(-)

P(-) = P(-|C)P(C) + P(-|C')P(C')

P(-) = (0.2 * 0.3) + (0.25 * 0.7) = 0.235

Therefore, P(C|-) = (0.2 * 0.3)/0.235

P(C|-) = 0.2553

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