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2 years ago

Name a number that is an integer, but not whole number.

Mathematics

1 answer:

tekilochka [14]2 years ago

4 0

Answer:

-1

Step-by-step explanation:

All negative integers are not whole numbers

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How to find the missing numbers in two digit division

abruzzese [7]

Answer:

Divide the first number of the dividend (or the two first numbers if the previous step took another digit) by the first digit of the divisor. Write the result of this division in the space of the quotient. Multiply the digit of the quotient by the divisor, write the result beneath the dividend and subtract it.Jun

Step-by-step explanation:

pls brainlist

3 0

3 years ago

A can of soda is placed inside a cooler. As the soda cools, its temperature T (x) in degrees celsius is givien by the following

wel

Answer:

Initial 18 degrees Celsius

After 20 minutes, 5 degrees Celsius

Step-by-step explanation:

It’s initial temperature can be calculated as at the time when x = 0

When x = 0, the temperature is -6+24 = 18 degrees Celsius

This is because the exponent part equals 1 since anything raised in to the power of zero is one.

After twenty minutes,

T(x) = -6 +24e^-0.038(20)

T(x) = -6 + 11.224 = 5.224

And that is approximately 5 degrees Celsius to the nearest degree

8 0

2 years ago

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago

Factor the polynomial 16b^4+30b^3-12b^2

Lelu [443]

Answer:

2b²(8b²+15b-6)

Step-by-step explanation:

16 $b^{4}$ +30b³-12b²

2b²(8b²+15b-6)

This is not further factorable. If you want to find the roots, you'd have to use the quadratic formula for the polynomial in the parentheses. Therefore that is our final answer.

4 0

3 years ago

One side of a triangle is 3 times the second side. The third side is 17 feet longer than the second side. The perimeter of a

liberstina [14]

Answer:

Side 1=21 ft, Side 2=7, Side 3=24

Step-by-step explanation:

52 = (3x) + (x) + (x+17) -> 52 = 5x + 17 -> 5x = 35 -> x = 7

Plus 7 into the equation whenever you see an x.

7 0

2 years ago