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olga55 [171]
3 years ago
13

The area of a rectangle is 506 square metre. If its length is 23 metre, then find its breadth?

Mathematics
2 answers:
Debora [2.8K]3 years ago
5 0

Answer:

<u>2</u><u>2</u><u>m</u><u> </u><u>is </u><u>the </u><u>breadth </u><u>of </u><u>the </u><u>rectangle</u><u>.</u>

Step-by-step explanation:

Given:

  • Area of Rectangle is 506 m² .
  • Length of the Rectangle is 23m.

\:

To Find:

  • Breadth of the rectangle.

\:

Solution:

As, we know,

{ \boxed{ \pink{Area _{(rectangle)} \:  = length \times breadth}}}

➝ 506m² = l × b

➝ 506m² = 23 × b

➝ b = 506/23 = 22

Hence, Breadth of the Rectangle is <u>2</u><u>2</u><u>m</u><u>.</u><u> </u>

\:

<h3><u>Check</u><u>:</u><u> </u></h3>

Area = length × breadth

➝ 23 × 22

➝ 506m²

<h2>______________________</h2>

{ \sf{Additional  \: Information}}

\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf{ \green{ Formulas\:of\:Areas:-}}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}

Zolol [24]3 years ago
4 0

Answer:

The area of a triangle can be determined with the two side lengths, the length and breadth/width multiplied.

x = unknown value of breadth/width

23 = length

506 = the area of the two lengths multiplied

23(x) = 506

/23        /23

x = <u>22</u>, 22 metres is it's breadth.

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