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3 years ago

Need assistance on some geometry

Mathematics

1 answer:

lukranit [14]3 years ago

8 0

Answer:

So I can't actually put a picture in, put heres the easiest way to understand this. If it says y-1, take the coordinates for y, and subtract 1. do that to all of them, not just 1. For example, R is 4,1. To translate it, you would take the y coordinate (1) and subtract 1. We know to do this because it shows translation x,y)->(x,y-1). Thus, the new point would be 4,0. apply this to all of the points.

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Explain how you know whether 1/15 is equal a terminating decimal or

Ulleksa [173]

The lame answer is that you put it into a calcuator and see.

The more formal way you know is if, when the fraction is reduced, the denominator's only prime factors are 2s or 5s. If that's the case, the fraction will terminate. If you have any prime factor other than 2 or 5, it will repeat.

But knowing that "2 or 5 prime factor" idea would have to be something specifically taught in your class (or a prerequisite class).

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3 years ago

A finite set of points in the plane has the property that the triangle formed by any 3 of them has area less than 1.Prove that t

Ainat [17]

Explanation:

All of the points must be contained within a circle that will circumscribe an equilateral triangle of area 1. (We refer to this as the inscribed triangle.) Any points on the circle that do not form an equilateral triangle will form a triangle with an area less than 1. Likewise for any points within the circle.

The circle can be circumscribed by an equilateral triangle whose side length is double that of the inscribed triangle. Since the side length is double, the circumscribing triangle will have an area 2² = 4 times that of the inscribed triangle.

The inscribed triangle has an area of 1, so the circumscribing triangle must have an area of 4.

3 0

3 years ago

Yea yea you know i need help my brains tiny thank you for everything and everyone helping

Darina [25.2K]

Answer: r=6

Step-by-step explanation:

Step 1: Substitute for the known variables

we know that the formula to find the volume of a cylinder is V= πr²h

π= 3.14

h= 12

r= ?

v=1,357

Plugging the numbers we know into the formula, we get:

1,357= 3.14xr²x12

1,357= 3.14x12xr² (because with the commutative property of multiplication you can multiply in any order)

1,357= 37.68 x r²

Step 2: Get the variable term (the letter term) on the left

37.68 x r²= 1,357

Now, divide by 37.68. (I know to divide because when you switch the 37.68x r² the other way around to r²x37.68, you are clearly multiplying and must do the inverse operation (opposite of multiplication; division) to solve the problem.

So,

r²= 1357÷37.68

r²= 36.0138004 ----> about 36.

r²= 36

This equation isn't over yet because we still have the exponent on the r. Whenever you see a letter squared (to the power 2) in an equation, the "inverse operation" is to take the square root of both sides. Look:

r²= 36

The square root of r² is just r, because r x r = r²

The square root of 36 is 6, because 6x6=36.

Now we have :

r= 6

Step 3: Check

Now we have all the variables. To check to make sure the radius is correct, "plug in"

V= π r²h

1,357= 3.14x6²x12

1,357= 3.14x36x12

1,357= 113.04x12

1,357= 1356.48

They said in the question that the volume is APPROXIMATLEY 1357, so I can just round 1356.48 --> 1356.5---> 1357. Now I am sure that the radius is 6.

Hope this helps :)) also brainliest would be appreciated :D

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2 years ago

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Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4

steposvetlana [31]

$f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}$

$\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}$

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4 years ago

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What number is 12 more than 43

Nata [24]

55. If it says 12 more, you add 12 to 43 to get 55.

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3 years ago

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