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3 years ago

100 points please help ! What is the name of the line of reflection for the pair of figures

Mathematics

2 answers:

Arlecino [84]3 years ago

4 0

Answer:

Hey!

I think the line must be LINE R

Step-by-step explanation:

As you can see it must be the Line of Reflection for both figures because it is EQUIDISTANT (equal distance from the 2 shapes). It runs PARALLEL in angle to the shapes too...

It can't be Line P because the line does not produce equal shapes on either side of it...

It can't be Line Q because it only provides the reflection result on one of the shapes, not BOTH...

So your answer is Line R

<h2><u>I HOPE THIS HELPED YOU!</u></h2>

**pls let me know if its wrong**

mestny [16]3 years ago

3 0

Line r I’m pretty sure since the line of reflection is pretty much the midpoint of something that also points in the same direction.

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The perimeter of a rectangle is 72 in. The base is 3 times the height. Find the area of the rectangle

Ulleksa [173]

Answer:

243 inches squared

Step-by-step explanation:

1) The total perimeter for each part is 8x.

2) 72 divided by 8 = 9

3) height = 9 base = 27

4) 9 x 27 = 243 inches squared

8 0

4 years ago

One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples

JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± $t_{n_1+n_2-2;1-\alpha /2}$ * $Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ ]

$Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11$

$t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708$

[(82.3-81.2) ± 1.708* (6.11* $\sqrt{\frac{1}{15}+\frac{1}{12} }$ ]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

3 0

3 years ago

Which of the following is a reasonable estimated answer to the following problem? 989,867 ÷ 999

kolezko [41]

991 if you round it off.

990.8
Above 5 so go up one

5 0

3 years ago

Read 2 more answers

X ÷ 8 = 8<br>a: 16<br>b: 56<br>c: 62<br>d: 64

Mariulka [41]

The answer is D!

64 divided by 8 is 8!