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Dovator [93]
3 years ago
5

Mike ate 1 3 of a bag of peanuts at the game, and on the way home he ate 1 3 of what was left. How much of the bag of peanuts di

d mike eat on the way home?
A) 1 3
B) 1 6
C) 1 9
D) 2 9
Mathematics
1 answer:
svlad2 [7]3 years ago
7 0

Mike ate 1 / 3 of a bag of peanuts at the game, then there left

1-\dfrac{1}{3} =\dfrac{3}{3} -\dfrac{1}{3}=\dfrac{2}{3}.

On the way home he ate 1 / 3 of what was left, that is he ate 1 / 3 from 2 / 3 and this is

\dfrac{1}{3} \cdot \dfrac{2}{3} =\dfrac{1\cdot 2}{3\cdot 3} =\dfrac{2}{9}.

On the way home Mike ate 2 / 9 of a bag of peanuts.

Answer: Correct choice is D.

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