No solution but the equation is true
The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
brainly.com/question/13513438
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Answer:
The amount of acid in third container is =42%
Step-by-step explanation:
Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .
Let, the volume of first container is = x
Then , the volume of second container = (x+ x of 50%)
= x + 0.5 x
= 1.5 x
Therefore the amount of acid in first container
= 0.3 x
The amount of acid in second container
= 0.75x
Total amount of acid= 0.3x + 0.75x = 1.05 x
Total amount of solution = x+1.5x = 2.5x
The amount of acid in third container is =
%
= 42%
Answer:
y+3 = 1/2 (x-4)
Step-by-step explanation:
We can write the equation in point slope form
y-y1 = m(x-x1)
The slope is m and the point is (x1,y1)
y - -3 = 1/2(x -4)
y+3 = 1/2 (x-4)
Answer:
y=-4x+7
Step-by-step explanation:
You put the points on a graph in desmos and then in a new line put the y=-4x+ and Playa round with numbers until you hit the point