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lozanna [386]
3 years ago
10

If the angles 2xº and 4yº are complementary, find the value of x + 2y.

Mathematics
1 answer:
ivolga24 [154]3 years ago
3 0

Answer:

Solution given:

the angles 2xº and 4yºare complementary

so

2x+4y=90°

dividing both side by 2we get

x+2y=45°

<u>the value of x + 2y</u><u> </u><u>i</u><u>s</u><u> </u><u>4</u><u>5</u><u>°</u><u>.</u>

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The sum of the measures of the angles of a triangle is 180°. The middle-sized angle measures 3° more than 2 times the smallest a
Anit [1.1K]

Answer:

13° , 29° , 138°

Step-by-step explanation:

let x be the smallest angle , then

2x + 3 is the middle angle and

2x + 3 + 109 is the largest angle

summing the 3 angles and equating to 180

x + 2x + 3 + 2x + 3 + 109 = 180 , that is

5x + 115 = 180 ( subtract 115 from 180 )

5x = 65 ( divide both sides by 5

x = 13

2x + 3 = 2(13) + 3 = 26 + 3 = 29

2x + 3 + 109 = 29 + 109 = 138

the 3 angles are 13° , 29° , 138°

6 0
2 years ago
BRAINLIESTI HAVE 10 MINS
VladimirAG [237]
Correction -125* I think
7 0
3 years ago
Mr. Sonny's science class is calculating the average number of blinks per minute. Jan blinks 57 times in 3 minutes. What is her
Vlada [557]

b. Every 24 minutes

Step-by-step explanation:

A neon sign blinks every 6 minutes, and another sign blinks every 8 minutes.

The first step is to:

Find and list multiples of each time each neon sign blinks.

This means, we find the Multiples of 6 and 8

Multiples of 6:

6, 12, 18, 24, 30, 36

Multiples of 8:

8, 16, 24, 32, 40

The first and common multiple of 6 and 8.

Therefore, the Least common multiple [LCM(6, 8) ] = 24

Hence, they often blink at the same time every 24 minutes.

Therefore, option b.Every 24 minutes is correct.

please mark me brainliest!

3 0
2 years ago
Read 2 more answers
What goes into 55 and 11
soldier1979 [14.2K]
10 5's go into 55 and
1 10 goes into 11

The answers I gave are only if you want them in 10's
5 0
3 years ago
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Find the balance in the account. $2,500 principal earning 4%, compounded quarterly, after 4 years
Helen [10]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad  \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2500\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &4 \end{cases} \\\\\\ A=2500\left(1+\frac{0.04}{4}\right)^{4\cdot 4}\implies A=2500(1.01)^{16}\implies A\approx 2931.4466123

3 0
3 years ago
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