The answer would be (3,7) in the first quadrant
Answer:
b
Step-by-step explanation:
Answer:
The two solutions are given as and
Step-by-step explanation:
As the given equation is
So the corresponding equation is given as
Solving this equation yields the value of m as
Now the equation is given as
Here m1=-8, m2=1 so
The derivative is given as
Now for the first case y(t=0)=1, y'(t=0)=0
So the two equation of co-efficient are given as
Solving the equation yield
So the function is given as
Now for the second case y(t=0)=0, y'(t=0)=1
So the two equation of co-efficient are given as
Solving the equation yield
So the function is given as
So the two solutions are given as and
Answer:
Yes, the graph makes it appear as if sales increased three folds.
Step-by-step explanation:
The graph presented by the advertising company is misleading, as it attempts to exaggerate the effect of its advert on sales. This can be attributed to the scale which is isn't uniform.
Last year sale was about 137000 and it grew to 150000 as a result of advertisement.
But from the bar chart, it seems there was three times increase in sales.
Answer:
v_top = 2400 mi/hr
v_w = 400 mi/h
Step-by-step explanation:
Given:
- Total distance D = 4800 mi
- Headwind journey time taken t_up= 3 hr
- Tailwind journey time taken t_down = 2 hr
Find:
Find the top speed of Luke's snow speeder and the speed of the wind.
Solution:
- The speed of Luke v_l is in stationary frame is given by:
v_l = v_w + v_l/w
Where,
v_w: Wind speed
v_l/w: Luke speed relative to wind.
- The top speed is attained on his returned journey with tail wind. We will use distance time relationship to calculate as follows:
v_top = D / t_down
v_top = 4800 / 2
v_top = v_down = 2400 mi/hr
- Similarly his speed on his journey up with head wind was v_up:
v_up = D / t_up
v_up = 4800 / 3
v_up = 1600 mi/hr
- Now use the frame relations to find the wind speed v_w:
v_down = v_w + v_l/w
v_up = -v_w + v_l/w
- Solve equations simultaneously:
2400 = v_w + v_l/w
1600 = -v_w + v_l/w
4000 = 2*v_l/w
v_l/w = 2000 mi/h
v_w = 400 mi/h