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3 years ago

6

32÷891 using long division

2 answers:

valentinak56 [21]3 years ago

5 0

It would be 0.03591470258136924803591470258136924803

Alinara [238K]3 years ago

5 0

It would be 27 with a remainder

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From its founding through 2012, the Rock and Roll Hall of Fame has inducted 303 groups or individuals. Forty-seven of the induct

motikmotik

The probability of inductees who are female will be 0.155.

<h3>How to illustrate the probability?</h3>

Question: What proportion of inductees have been female or have included female members?

From the information, 303 groups or individuals and forty-seven of the inductees have been female or have included female members.

Therefore, the proportion will be:

= 47/303

= 0.155

Learn more about probability on:

brainly.com/question/24756209

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8 0

2 years ago

Given ABCD - WXYZ, Find the length of the segment AD, If Ab=12 WX=20 and WZ=8

hodyreva [135]

Answer:

8

Step-by-step explanation:

the length of segment AD would be 8 since segment AD and segment WZ are equal in length!

8 0

3 years ago

The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n

GarryVolchara [31]

Answer:

$(-1,1),(4,-2)$

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point $(x,y)$

Distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}$

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

$34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]$

Put $(x,y)=(-1,1)$

$34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34$

which is true. So, $(-1,1)$ can be a vertex

Put $(x,y)=(4,-2)$

$34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34$

which is true. So, $(4,-2)$ can be a vertex

Put $(x,y)=(1,1)$

$34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22$

which is not true. So, $(1,1)$ cannot be a vertex

Put $(x,y)=(2,-2)$

$34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22$

which is not true. So, $(2,-2)$ cannot be a vertex

Put $(x,y)=(4,-1)$

$34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30$

which is not true. So, $(4,-1)$ cannot be a vertex

Put $(x,y)=(-1,4)$

$34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70$

which is not true. So, $(-1,4)$ cannot be a vertex

So, possible points for the vertex are $(-1,1),(4,-2)$

7 0

3 years ago

Read 2 more answers

Circle $O$ is located on the coordinate plane with center at $(2,3)$. One endpoint of a diameter is at $(-1,-1)$. What are the c

Triss [41]

Answer:

(6,7)

Step-by-step explanation:

6 0

3 years ago

Solve the following equation. Express your answer as an integer, simplified fraction, or decimal rounded to two decimal places.

Nostrana [21]

7=4w+19
7-19 = 4w+19-19
-12 = 4w
-12/4 = 4w/4
-3 = w

8 0

3 years ago