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kakasveta [241]
2 years ago
10

Using your knowledge of 2- and y-intercepts, which graph matches the equation y = x + 2x - 3?

Mathematics
1 answer:
mestny [16]2 years ago
3 0

Answer:

ANSWER (A.

Step-by-step explanation:

HOPE IT HELP'S !

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Using the exchange rate £1 = $1.34, calculate how many £ are in $7.25. Give your answer rounded to 2 dp.
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Answer:

£5.41

Step-by-step explanation:

7.25/1.34 = 5.41044...

Round = 5.41

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A bus travels with a constant speed of 48 miles per hour. How long will it take to travel 60 miles? Write your answer as a decim
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Question 9 of 10
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A is the answer

// x = -2(y + 3)2-1

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2 years ago
Henry buys a large boat for the summer, however he cannot pay the full amount of $32,000 at
Anna007 [38]

Answer:

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

Step-by-step explanation:

Loan payment per month=Amount to pay÷discount factor

Mathematically  P=A÷D

where D is the discount factor calculated using the formula;

\frac{(1+i)^n-1}{i(1+i)^n}

where i=periodic interest rate=annual rate divided by number of payment periods

A is the amount to pay after downpayment

P is the loan monthly payment amount

n=number of periodic payments=payments per year times number of years

⇒In this question you find the discount factor then divide the amount remaining to pay with the discount factor to get monthly payments

Given;

Cost of boat=$32000

Down payment=$14000

Loan to pay=$32000-$14000=$18000

Annual rate=5.5%=i=5.5%÷12=0.458%⇒0.00458

Periodic payments, n=4×12=48

Finding the discount factor D;

D=\frac{(1+i)^n-1}{i(1+i)^n} \\\\\\D=\frac{(1+0.00458)^{48} -1}{0.00458(1+0.00458)^{48} } \\\\\\D=\frac{1.2455-1}{0.005703} \\\\\\D=\frac{0.2455}{0.005703} =43.05

To get the amount to pay monthly divide the loan to pay with the discount factor

=\frac{18000}{43.05} =418.14

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

8 0
3 years ago
How to get the volume of a answer
Eduardwww [97]
Mass* length * breadth
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