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Kitty [74]
2 years ago
10

400 students were randomly sampled from a large university, and 289 said they did not get enough sleep. Conduct a hypothesis tes

t to check whether this represents a statistically significant difference from 50%, and use a significance level of 0. 1
SAT
1 answer:
jarptica [38.1K]2 years ago
4 0

Answer:

The sample proportion represents a statistically significant difference from 50%

Explanation:

The sample proportion is the same as 50%

Alternate hypothesis: The sample proportion is not the same as 50%

z = (p' - p) ÷ sqrt[p(1 - p) ÷ n]

p' is sample proportion = 289/400 = 0.7225

p is population proportion = 50% = 0.5

n is number of students sampled = 400

z = (0.7225 - 0.5) ÷ sqrt[0.5(1 - 0.5) ÷ 400] = 0.2225 ÷ 0.025 = 8.9

The test is a two-tailed test. Using a 0.01 significance level, critical value is 2.576. The region of no rejection of the null hypothesis is -2.576 and 2.576.

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<h3>Distances and speed</h3>

Let the distance from P to Q be "d"

Since the formula for calculating speed is expressed as:

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If he drives back at an average speed of 45mph and 2 mintes less, then;

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d = 45 (t - 0.033)

Equating both distances

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Get the distance from P to Q:

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Learn more on speed and distance here: brainly.com/question/4931057

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