Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be perpendicular, their slopes have to be the negative reciprocal of each other. (Basically flip the sign +/- and the fraction(switch the numerator and the denominator))
For example:
Slope = 2 or 
Perpendicular line's slope = 
(flip the sign from + to -, and flip the fraction)
Slope = 
Perpendicular line's slope = 
(flip the sign from - to +, and flip the fraction)
y = 1/3x + 4 The slope is 1/3, so the perpendicular line's slope is 
or -3.
Now that you know the slope, substitute/plug it into the equation:
y = mx + b
y = -3x + b To find b, plug in the point (1, 2) into the equation, then isolate/get the variable "b" by itself
2= -3(1) + b Add 3 on both sides to get "b" by itself
2 + 3 = -3 + 3 + b
5 = b
y = -3x + 5
There is no solution for this equation since they have the same slope, x/1. The only difference between these two is that their y intercepts are different meaning that they will be parallel lines that will never intersect among one other. For example, think of it as two separate lines that are have the same slope and never gain more distance/units from one another.
Solve:
To solve, you have to get one of this equations into a Ax+By=C equation form, standard equation. Let’s change y=x+4 into a standard equation.
We have to get x and y together and 4 as C.
So let’s subtract x from both sides;
y=x+4
-x -x
————————
-x+y=4
This is a standard equation.
Now let’s substitute.
take the standard equation and plug in y which is x+4 since there is a equation meaning it’s y=x+4
-x+(x+4)=4
Let’s simplify this mess.
-x+x equals 0. So we are left with 4=4.
Subtract 4 from both sides and we get 0=0
This means there is no solution. Hoped this helped.
Answer:
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ima edit my answer
Step-by-step explanation:
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2/2, 4/4, 5/5, 7/7, or any fraction with the same numerator and denominator will be equivalent. All fractions equal 1.
