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iren [92.7K]
3 years ago
14

Is 0.65 repeating greater than or less than 13/20?

Mathematics
2 answers:
vova2212 [387]3 years ago
8 0

Answer:

its equal

Step-by-step explanation:

V125BC [204]3 years ago
7 0

Answer:

Since 13/20 is exactly 0.65, then 0.6565656565......(repeating) is greater than 13/20.

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Convert 1.5 cubic meter to ______ cubic centimeters.
Vedmedyk [2.9K]

Answer:

1500000 cubic centimeters

6 0
2 years ago
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The number of entrees purchased in a single order at a Noodles & Company restaurant has had an historical average of 1.35 en
trasher [3.6K]

Answer:

a) 0.3571

b) The p-value is 0.362007.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 1.35

Sample mean, \bar{x} = 1.4

Sample size, n = 26

Alpha, α = 0.01

Sample standard deviation, s = 0.7

First, we design the null and the alternate hypothesis

H_{0}: \mu = 1.35\text{ entrees per order}\\H_A: \mu > 1.35\text{ entrees per order}

We use One-tailed t test to perform this hypothesis.

a) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n-1}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{1.4 - 1.35}{\frac{0.7}{\sqrt{25}} } = 0.3571

b) The p-value at t-statistic 0.3571 and degree of freedom 25 is 0.362007.

4 0
3 years ago
Carlos drank 2740 mL of water after football practice. How many liters did he drink
Bas_tet [7]
2740/1000= 2.74

So the answer is 2.74 Liters
4 0
3 years ago
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What is the wavelength of a 320 Hz sound traveling 330 m/s?
maw [93]

Answer:1.03125 meter

Step-by-step explanation:

Velocity =330 meter per second

Frequency =320 Hertz

wavelength=velocity ➗ frequency

Wavelength=330 ➗ 320

Wavelength=1.03125 meter

8 0
4 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
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