Question

24 , Factor: x²-9 A (x + 3XX-3) B (x+3)2 с (x-3) (x+3)(x+3)

Answer 1

Answer:

(x-3)(x+3)

Step-by-step explanation:

We are given the expression $\displaystyle \large{x^2-9}$:—

To factor this expression, we have a formula for it which is difference of two squares:—

$\displaystyle \large{a^2-b^2=(a+b)(a-b)}$

You can also swap from $\displaystyle \large{(a+b)(a-b)}$ to $\displaystyle \large{(a-b)(a+b)}$ via multiplication property.

From the expression, factor using the formula above:—

$\displaystyle \large{x^2-9=(x^2)-(3)^2}\\\displaystyle \large{x^2-9=(x-3)(x+3)}$

Therefore, the factored expression is:—

$\displaystyle \large{\boxed{(x-3)(x+3)}}$

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