All categories

2 years ago

Prince owe R24000 every month he pays R600 . determine after how many months will she owe R3000

Mathematics

1 answer:

ollegr [7]2 years ago

8 0

Answer:

Step-by-step explanation:

If prince owes ₹3000, the debt will have been reduced by ₹24000-3000 = ₹21000. The amount of time it takes to reduce the debt by that amount is ...

₹21000/(₹600/mo) = 35 mo

After 35 months, prince will owe ₹3000.

You might be interested in

The Controlled Substances Act of 1970 categorized drugs such as morphine and cocaine as Schedule ________ drugs. A. IV B. I C. I

Feliz [49]

I believe the answer is

C. II

8 0

3 years ago

URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (39pt

MariettaO [177]

Answer:

The first transit on one side of the trench is 18 ft higher than the other side of the trench. The transit is set at 4.5 above ground, therefore the transit lens is 18' + 4.5' = 22.5' above the location on the other side of the trench. The angle of depression is the angle formed by the horizontal and the line of sight to the other side and it is given as 31°. This forms a right angle triangle with height of 22.5' and an interior angle of 31°, Then

tan( 31°) = Height / base, with the base representing the width of the trench

base = Height / tan(31°) = 22.5' / tan(31°) = 37.45' is the width of the trench

4 0

3 years ago

Read 2 more answers

Can anyone help me about question 2

madreJ [45]

9514 1404 393

Answer:

3(4/3)^2543

Step-by-step explanation:

Using logarithms base 2, we have ...

$(a_n)^{\log{a_n}}=(a_{n+1})^{\log{a_{n-1}}}\\\\(\log{a_n})(\log{a_n}) = (\log{a_{n-1}})(\log{a_{n+1}}) \\\\ \dfrac{\log{a_{n+1}}}{\log{a_{n}}}=\dfrac{\log{a_n}}{\log{a_{n-1}}}=\dots\dfrac{\log_2{16}}{\log_2{8}}=\dfrac{4}{3}$

That is, the ratio of each term to the previous is a constant equal to 4/3. This is the definition of a geometric sequence. This sequence has first term 3 and common ratio 4/3, so the general term is ...

$\log_2 a_n=3\left(\dfrac{4}{3}\right)^{n-1}$

and the 2544th term is ...

$\boxed{\log_2{a_{2544}}=3\left(\dfrac{4}{3}\right)^{2543}}$

8 0

3 years ago

Question:

Allisa [31]

We know that 24 is 160% more than some recommended number, let's call it "x." This means 1.6 times the recommended number equals 24. Therefore, all we need to do is solve for x.

$1.6x=24$

$x=\frac{24}{1.6}$

Make sense?

4 0

3 years ago

In the Triangle below, find X A. 10.3 B. 9.6 C. 84 D. 9

viva [34]

Isosceles triangle
9x + 3 = 84
9x = 81
x = 9

answer
D. 9

4 0

3 years ago

Prince owe R24000 every month he pays R600 . determine after how many months will she owe R3000​

Prince owe R24000 every month he pays R600 . determine after how many months will she owe R3000