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2 years ago

0.69 rounded to the nearest hundred

Mathematics

2 answers:

patriot [66]2 years ago

7 0

Answer:

0.07 Locate and underline the hundredths place (6) then look at the digit to the right (9):

0.069

Step 2: In this case, the digit to the right (9) is 5 or above. So, we add 1 to the hundredths place (6). The digit(s) after the (6) are replaced by zeros (or dropped)

Contact [7]2 years ago

5 0

Answer:

Step-by-step explanation:

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Roger Brown works for the sanitation department. He earns a salary of $721.00 biweekly. His boss gave him

liq [111]

Answer:

2249 dollars more

Step-by-step explanation:

52 weeks in one year so divide by 2 and then multiply by 721 and then take that amount and dubtract the new salary 20.995 and subtract the previous annual amount and then boom 2295 more

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3 years ago

The positive square root of 38 is between?

Oksanka [162]

It's between 6 and 7.

4 0

3 years ago

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

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3 years ago

Which ratios form a proportion?

LekaFEV [45]

I would say D. 10/16, 5/8
Hope This helps :)

4 0

3 years ago

What is 3x4 please tell me

Alinara [238K]

12 because if u had 3 groups of 4 that would be 3+3+3+3

8 0

3 years ago

Read 2 more answers