Question

What is the simplest form of the expression? 3sqrt(750)+3sqrt(2058)-3sqrt(48)?

Answer 1

The given expression is

$3 \sqrt{750}+ 3 \sqrt{2058}-3 \sqrt{48}$

We have to check out the factors of 750, 2058 and 48

$3 \sqrt{5^2 *30 } +3 \sqrt{7^2 *42} -3 \sqrt{4^2 *3}$

And square root of a perfect square number is the number itself.

That is

Square root of 25 is 5, square root of 49 is 7 and square root of 16 is 4.

So we will get

$3*5 \sqrt{30} +3*7 \sqrt{42} - 3*4 \sqrt{3} \\ = 15 \sqrt{30} + 21 \sqrt{42} -12 \sqrt{3}$

Answer 2

After solving it, I got 10^3sqrt6 Hope this helps