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Oksanka [162]
3 years ago
15

The sum of the base and height of a triangle is 14 cm. Which of the following equations could be used to find the maximum area o

f the triangle?
A) A = 0.5x^2 - 15x

B) A = -0.5x^2 + 7x

C) A = -x^2 + 10x

D) A = x^2 - 10x
Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Let the base of the triangle be <em>b</em> and the height be <em>h</em>.

The sum of the base and height is 14. Thus:

b+h=14

Recall that the area of a triangle is given by:

\displaystyle A=\frac{1}{2}bh

From the first equation, solve for either variable:

h=14-b

Substitute:

\displaystyle A=\frac{1}{2}b(14-b)

Distribute:

\displaystyle A=\frac{1}{2}(14b-b^2)

Distribute:

\displaystyle A=-0.5b^2+7b

Let <em>b</em> = <em>x</em>. Hence:

A=-0.5x^2+7x

Therefore, our answer is B.

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Read 2 more answers
The area of a triangular block is 49 square inches. If the base of the triangle is twice the height, how long are the base and t
andrezito [222]
1) Formula: area = height * base / 2

2) Call x the height:

height = x

base = 2x

3) State the equation:

(x)(2x) = 49 in^2

4) Solve the equation:

2x^2 = 49 in^s

x^2 = (49/2) in^2

x = √(49/2) in

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5) Solution:

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