50 Miles at an average rate
Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
A box-and-whisker plot is shown above a number line that extends from 70 to 100 with 1 unit markings. The box extends from 79 to between 90 and 91 with a division at 89. There is also a point marked at 89. The whisker on the left extends from 75 to 79. The whisker on the right extends from between 90 and 91 to 93.
i hope this helps u and makes sense :))
1st angle = 2 * 2nd angle
3rd angle = 2nd angle + 80
1st angle = 2x
2nd angle = x
3rd angle = 80 + x
2x + x + 80 + x = 180
4x = 100
x = 25
1st angle = 50
2nd angle = 25
3rd angle = 105
