Answer:
Possible values of x are 50 < x < 110.
Step-by-step explanation:
Consider the perimeter of the field:
2x + 2(x + 30) < 500
2x + 2x + 60 < 500
4x < 440
x < 110.
Consider the area of the field:
x(x + 30 ) > 4000
x^2 + 30x - 4000 > 0
(x - 50)(x + 80) > 0
The critical values are x = -80 and 50.
As x is a width it must be positive so x > 50.
You could write 42/20 for #60.
Answer:
Area of rectangle=9×17=153 SQ.ft
Area of semi-circle=π9'2/2
Area of traingle=(1/2)×7×9=31.5
I don't know if this is the answer that you are looking for, but would the answer be all solutions?
The slope = -0.8
Hopefully this helped you!
