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3 years ago

9(-4-3)=? Please help

Mathematics

2 answers:

Annette [7]3 years ago

5 0

This is the answer 9(-4-3) = -63

Vlad1618 [11]3 years ago

3 0

Answer:-63

Step-by-step explanation:

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Which transformations are needed to change the parent cosine function to y = 3 cosine (10 (x minus pi))?

Alekssandra [29.7K]

Answer:

See Explanation

Step-by-step explanation:

Given

New function: $y = 3 \cos(10 (x -\pi))$

We can assume the parent function to be:

$y = \cos (x)$

The new function can be represented as:

$y = A*\cos((\frac{2\pi}{B})(x-c))$

Where

A = Vertical stretch factor

B = Period

C = Right shift

By comparison:

$y = A*\cos((\frac{2\pi}{B})(x-c))$ to $y = 3 \cos(10 (x -\pi))$

$A = 3$

$c = \pi$

$\frac{2\pi}{B} = 10$

Solve for B

$B = \frac{2\pi}{10}$

$B = \frac{\pi}{5}$

Using the calculated values of $A,\ B\ and\ c.$ This implies that, the following transformations occur on the parent function:

Vertically stretched by $3$
Horizontally compressed by $\frac{\pi}{5}$
Right shifted by $\pi$

5 0

3 years ago

Read 2 more answers

23--2c=41 sorry last question

svlad2 [7]

C=9 np if u need anymore I gotchu

8 0

3 years ago

Read 2 more answers

How to find the θ in this equation: tan(θ+16°)=1/tan(θ+60°) by using the trigonometric identities?thanks

DedPeter [7]

Answer:

$\huge \theta =7°$

Step-by-step explanation:

$tan( \theta + 16 \degree) = \frac{1}{tan( \theta + 60 \degree) } \\ tan( \theta + 16 \degree) =cot( \theta + 60 \degree) \\ tan( \theta + 16 \degree) = tan \{90 \degree - (\theta + 60\degree) \} \\ \theta + 16 \degree = 90 \degree - \theta - 60\degree \\ \theta +\theta = 30 \degree - 16\degree \\2 \theta = 14 \degree \\ \theta = \frac{14 \degree}{2} \\ \huge \red{ \boxed{\theta =7 \degree}}$