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aksik [14]
4 years ago
5

Find the value of a and b. a) 144, 67 b) 144, 36 c) 113, 67 or d) 113, 36

Mathematics
1 answer:
TEA [102]4 years ago
7 0
Work shown above! Answer is
a = 144
b = 67

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padilas [110]

Answer:

The answer is D

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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marshall27 [118]

Answer:

AAS

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3 0
3 years ago
It has been hypothesized that the standard deviation of the germination time of radish seeds is 8 days. The standard deviation o
Yanka [14]

Answer:

\chi^2 =\frac{60-1}{64} 36 =33.19

The degrees of freedom are:

df= n-1= 60-1= 59

And the p value would be given by:

p_v =2*P(\chi^2 >33.19)=0.0053

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true deviation is different from 8 days.

Step-by-step explanation:

Data given

n=60 represent the sample size

\alpha=0.01 represent the confidence level  

s^2 =6^2 =36 represent the sample variance obtained

\sigma^2_0 =8^=64 represent the value that we want to test

Hypothesis to test

We want to verify if the true deviation is equal to 8 days o not, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 64

Alternative hypothesis: \sigma^2 \neq 64

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

Replacing we got:

\chi^2 =\frac{60-1}{64} 36 =33.19

The degrees of freedom are:

df= n-1= 60-1= 59

And the p value would be given by:

p_v =2*P(\chi^2 >33.19)=0.0053

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true deviation is different from 8 days.

6 0
3 years ago
A college entrance exam company determined that a score of 2222 on the mathematics portion of the exam suggests that a student i
kolbaska11 [484]

Answer:

Yes, Students are scoring above 2222 on the math portion of the​ exam.

Step-by-step explanation:

We are given that a college entrance exam company determined that a score of 2222 on the mathematics portion of the exam suggests that a student is ready for​ college-level mathematics i.e., population mean is 22.

Null Hypothesis, H_0 : \mu = 22 {Students are scoring equal to 2222 on the math portion of the​ exam}

Alternate Hypothesis, H_0 : \mu > 22 {Students are scoring above 2222 on the math portion of the​ exam}

Also, a random sample of 150 students who completed this core set of courses results in a mean math score of 22.7 on the college entrance exam with a standard deviation of 3.93 i.e.;

Sample mean, Xbar = 22.7    and Sample standard deviation, s = 3.93

The Test statistics is given by;

                            Z = \frac{Xbar -\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

Test Statistics = \frac{22.7 -22}{\frac{3.93}{\sqrt{150} } } ~ t_1_4_9

                        = 2.1815

Since, we are not given with the significance level, so we assume it to be 5%. At 5% significance level t table gives critical value of 1.6578 at 149 degree of freedom. Since our test statistics is more than the critical value so we reject null hypothesis as our test statistics fall in the rejection region.

Therefore, we conclude that Students are scoring above 2222 on the math portion of the​ exam.

7 0
3 years ago
Write an<br> equation of a line with the given slope and y-intercept.<br> m=-2, b=3
GuDViN [60]

Answer:

y=-2x+3

Step-by-step explanation:

y=mx+b

m=-2,b=3

so, y=-2x+3

hopes this helps

4 0
3 years ago
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