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igomit [66]
3 years ago
14

Solve the inequality and enter your solution as an inequality. 8 + x>4​

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0

if any concerns or questions on solution, just comment

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Simplify<br> (7x - 7)(x + 1)
Nadusha1986 [10]

We will use the FOIL method to solve this.

(7x-7)(x+1)

Multiply 7x by x. Then, multiply 7x by 1. Then, multiply -7 by x. Then, Multiply -7 by 1.

7x^{2} + 7x - 7x -7

Now, we need to simplify by combining like terms.

7x^{2} -7

If you look, -7x and 7x are gone. This is because they cancel each other out.

I hope this helped and maybe consider giving me brainliest :)

5 0
3 years ago
Carrie runs 11.5 miles and five hours at a study pi runs 11.5 miles in five hours at a steady pace how long does it take her to
alukav5142 [94]

dividing 11.5 by 5 gives you the unit rate, then you just multiply that answer by 2 and you should be okay

8 0
3 years ago
What is the overall charge for neon,oxide, copper, and tin ?
Finger [1]

Answer:

Neon is stable, hence has no charge.

Oxide (O2-) has a charge of -2

Cooper (Cu2+) has a charge of +2

Tin (Sn2+) has a charge of +2

hence overall charge = -2+2+2

<em><u>Over</u></em><em><u>all</u></em><em><u> </u></em><em><u>charge</u></em><em><u> </u></em>= +2

6 0
3 years ago
A property owner wants to build a cyclone fence around their property. The lot is rectangular, 110 feet by 270 feet. The fence i
dimulka [17.4K]

Answer:

total cost= $5,814

Step-by-step explanation:

Total linear feet measured: (110 x 2) + (270 x 2) = 760 linear ft

total sq ft= 760 x (7) = 5320 sq ft

total linear ft x labor= 760 x 1.70 = 1292 labor

Total sq ft x Cyclone fencing cost= 5320 x .85 = 4522

the total cost is 1292 + 4522 = $5,814

8 0
3 years ago
The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how
vichka [17]

Answer:

The number of bacteria after 8th will be 3840

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

A=A_0r^{n-1}

Where A is number of bacteria after n hours.

A_0 is bacteria present initially.

r is the common ration, in our problem it is given that bacteria doubles every hour. So, r=2

And n is the number of hours. In our problem we need amount of bacteria at the end of 8th hours. So, n=8

Plugging values in the formula we get,

A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840

So, number of bacteria after 8th will be 3840

3 0
3 years ago
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