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3 years ago

P = 215(1.005)t/3

Mathematics

1 answer:

Reil [10]3 years ago

6 0

Answer:

(D) 36

Step-by-step explanation:

0.5% = 0.5/100 = 0.005

It is given that the population (215) is predicted to increase by 0.5%. To know the value after increment, 215 has to be multiplied by (1 + 0.005) or 1.005.

In the equation P = 215(1.005)t/3, the value of t/3 has to be equal to 1 for 0.5% increase.

t/3 = 1

t = 3 years

Convert years to months.

n = 3 ⋅ 12 months

n = 36 months

The correct option is D.

Thanks!

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Drag the tiles to the correct boxes to complete the pairs.

Elza [17]

Answer:

Part 1) -7 → $\dfrac{y^2-y+6}{-2(y+7)}$

Part 2) 3/2 → $\dfrac{y^2-2y+1}{2y-3}$

Part 3) 1 → $\dfrac{5y^2-6y+1}{-5(y-1)}$

Part 4) -1/4 → $\dfrac{y(y+5)}{4y+1}$

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

we know that

To find out the non permissible replacements for y, equate the denominator of each expression equal to 0.

step 1

we have

$\dfrac{y^2-2y+1}{2y-3}$

Equate (2y-3) equal to 0.

$2y-3=0$

solve for y

Adds 3 both sides.

$2y=3$

Divide both sides by 2.

$y=\dfrac{3}{2}$

therefore

3/2 is the non permissible replacement for y.

step 2

we have

$\dfrac{y(y+5)}{4y+1}$

Equate (4y+1) equal to 0.

$4y+1=0$

Subtract 1 both sides

$4y=-1$

Divide by 4 both sides

$y=-\dfrac{1}{4}$

therefore

-1/4 is the non permissible replacement for y.

step 3

we have

$\dfrac{5y^2-6y+1}{-5(y-1)}$

Equate -5(y-1) equal to 0.

$-5(y-1)=0$

Divide by -5 both sides

$y-1=0$

Adds 1 both sides

$y=1$

therefore

1 is the non permissible replacement for y.

step 4

we have

$\dfrac{y^2-y+6}{-2(y+7)}$

Equate -2(y+7) equal to 0.

$-2(y+7)=0$

Divide by -2 both sides

$y+7=0$

Subtract 7 both sides

$y=-7$

therefore

-7 is the non permissible replacement for y

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3 years ago

A random sample of 10 observations was selected from a normal population distribution. The sample mean and sample standard devia

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Answer:

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Step-by-step explanation:

Given the following

sample size n = 10

standard deviation s = 3.2

Sample mean = 20

z-score at 95% = 1.96

Confidence Interval = x ± z×s/√n

Confidence Interval = 20 ± 1.96×3.2/√10

Confidence Interval = 20 ± (1.96×3.2/3.16)

Confidence Interval = 20 ± (1.96×1.0119)

Confidence Interval = 20 ± 1.9833

CI = {20-1.9833, 20+1.9833}

CI = {18.0167, 21.9833}

Hence the required confidence interval is 18.0167≤x≤21.9833

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3 years ago

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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3 years ago