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Elodia [21]
3 years ago
8

The price of a plane ticket has increased from $150 to $200. By what percent has the price increased?

Mathematics
2 answers:
Maslowich3 years ago
5 0

Answer:

It has increased 33%

kumpel [21]3 years ago
5 0

Answer:

33%

Step-by-Step

50/150 = 1/3 = 33%

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PLEASE HELP!!! I WILL MARK BRAINLEST!!!
storchak [24]

Answer:

Each hat is $5

Each mask is $3

Step-by-step explanation:

Hat= x dollars

Mask= y dollars

Now,

3 hats and 4 mask sold = $27

We can write

3x + 4y = 27

Adding the second equation (-1 times 1st equation) gives us;

3x + 6y = 33

-1* (3x + 4y = 27)

3x + 6y = 33

-3x -4y = 27

2y = 6

y = 6/2

***y = 3***

Now we replace y= 3 into 1st equation and solve for x:

3x + 4y = 27

3x + 4(3) = 27

3x + 12 = 27

3x + 15

x = 15/3

***x= 5***

Each hat costs $5

Each mask costs $3

6 0
3 years ago
If EF bisects CD.CG = 5x - 1, GD = 7x-13, EF = 6x - 4, and GF = 13. find EG.
Iteru [2.4K]

Answer:

EG = 19

Step-by-step explanation:

* Lets explain how to solve the problem

- If a line bisects another line that means the point of intersection

 divides the second line into two equal parts

∵ EF bisects CD at G

∴ CG = GD

∵ CG = 5x - 1

∵ GD = 7x - 13

∴ 7x - 13 = 5x - 1

* Lets solve the equation

∵ 7x - 13 = 5x - 1

- Subtract 5x from both sides and add 13 to both sides

∴ 7x - 5x = 13 - 1

∴ 2x = 12

- Divide both sides by 2

∴ x = 6

- Point G divides EF into two parts EG and GF

∴ EF = EG + GF

∵ EF = 6x - 4

- Substitute the value of x to find EF

∵ x = 6

∴ EF = 6(6) - 4 = 36 - 4 = 32

∴ EF = 32

∵ GF = 13

- Substitute the values of EF and GF in the equation of EF

∴ 32 = EG + 13

- Subtract 13 from both sides

∴ 19 = EG

* EG = 19

3 0
3 years ago
Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

#SPJ1

7 0
2 years ago
2 plus 2 is for times 20 is
Damm [24]
2+2=4 x 20=80 I hope this is what you were looking for
4 0
2 years ago
Read 2 more answers
17.
kifflom [539]

g \geqslant 5
A
3 0
3 years ago
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