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MaRussiya [10]
4 years ago
6

Line segment TS is tangent to circle O at point N.

Mathematics
1 answer:
garik1379 [7]4 years ago
7 0

Answer:

  148°

Step-by-step explanation:

The measure of the intercepted arc QN is twice the measure of inscribed angle QNT.

  arc QN = 2(74°) = 148°

_____

<em>Comment on the question and answer</em>

Your description "on the circle between points Q and N" is ambiguous. You used the same description for both points P and R. The interpretation we used is shown in the attachment. If point P is on the long arc NQ, then the measure of arc QPN will be the difference between 148° and 360°, hence 212°. You need to choose the answer that matches the diagram you have.

__

We call angle QNT an "inscribed angle" because it is a degenerate case of an inscribed angle. The usual case has the vertex of the angle separate from the ends of the arc it intercepts. In the case of a tangent meeting a chord, the vertex is coincident with one of the ends of the intercepted arc. The relation between angle measure and arc measure remains the same: 1 : 2.

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Find the unknown side length of the rectangle is 3 2/3 and if the area is 11m2
patriot [66]

Answer:

The width of the rectangle given is equal to 3m.

Step-by-step explanation:

In order to solve this question we need to know that the areas of the rectangle is equal to A_{rectangle} = (l)(w), where "l" is length and "w" is width. So know in order to solve this question we would have to find out the unknown width by using area and the length of the triangle. Based on the formula I wrote down earlier we can understand the following.....

A_{rectangle} = (l)(w)

\frac{A_{rectangle} }{l}  = \frac{(l)(w)}{l}

w = \frac{A_{rectangle} }{l}

Just now we found out the formula that we can use to solve for the width when we know the area and the length of the rectangle. Now in order to get the answer we just have to plug in the values we know, and we get........

w = \frac{A_{rectangle} }{l}

w = \frac{11m^{2} }{(3\frac{2}{3}m )}

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7 0
3 years ago
The circule by X^2 + Y^2- 2y-11=0
Sati [7]
X^2 + y^2 -2y-11=0

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x^2 + y^2 -2y + ? = 11 + ?

x^2 + y^2 -2y + 1 = 11 + ?

x^2 + y^2 -2y + 1 = 11 + 1

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3 years ago
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tatyana61 [14]
The answer is.... 3.532*10^-4
8 0
3 years ago
I need to find x &amp; y. plz answer i really need thisssss. only if correct :)
Leto [7]

Answer:

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Step-by-step explanation:

We can find x using the pythagorean thereom because ABD is a right triangle.(D is the point between segments with legnth 5 and 11)

AC^2 + CD^2 = AD^2

x^2 + 5^2 = 13^2

x^2 = 25 = 169

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x = 12

We may now find y using the pythagorean thereom because ABC is a right triangle. Right now we know x = 12

AC^2 + CB ^2 = AB^2

12^2 + 16^2 = y^2

144 + 256 = y^2

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<em>I hope this helps! :)</em>

5 0
3 years ago
Wich is the unknown number? which property did u use?
Gwar [14]
The answer is 9. because... (8+9) + 32= 49
3 0
3 years ago
Read 2 more answers
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